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IceJOKER [234]
3 years ago
12

s 4x \times 2y" align="absmiddle" class="latex-formula">
how do you simplify? ​
Mathematics
1 answer:
Dahasolnce [82]3 years ago
5 0

Answer:

24 x y

Step-by-step explanation:

Simplify the following:

3×4×2 x y

Hint: | Multiply 3 and 4 together.

3×4 = 12:

12×2 x y

Hint: | Multiply 12 and 2 together.

12×2 = 24:

Answer: 24 x y

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The mean finish time for a yearly amateur auto race was 186.32 minutes with a standard deviation of 0.305 minute. The winning​ c
uranmaximum [27]

Complete Question

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.305 minute. The winning car, driven by Roger, finished in 185.85 minutes. The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

Find their respective z-scores.

 Who had the more convincing victory?

A. Roger​ had a more convincing victory because of a higher z-score.

B. Karen a more convincing victory because of a higher z-score.

C. Roger had a more convincing victory, because of a lower z-score.

D. Karen a more convincing victory because of a lower z-score.

Answer:

The correct option is  D

Step-by-step explanation:

From the question we are told that

  The mean of the current year  is  \mu_c =  186.32 \  minutes

   The standard deviation is  \sigma_c  =  0.305 \  minutes

   The time taken by  the winning car for the current year  is  x =  185.85 \ minutes

  The mean of the previous  year  is  \mu_p =  110.7 \  minutes

   The standard deviation the previous  year  is  \sigma_p  = 0.115  \  minutes

 The time taken by  the winning car for the previous year  is  y =   110.48 \ minutes    

Generally the z-score for current year is mathematically evaluated as

     z_c  =  \frac{x- \mu_c}{\sigma_c }

=>     z_c  =  \frac{ 185.85- 186.32}{0.305 }

=> z_c  = -1.536

Generally the z-score for previous year is mathematically evaluated as

     z_p  =  \frac{y- \mu_p}{\sigma_p }

=>     z_p  =  \frac{ 110.48-110.7}{0.115  }

=> z_p  = -1.913

From the value obtained we see that  z_p  <  z_c , Hence  Karen had a more convincing victory because of the lower z -score.

5 0
3 years ago
In a survey, 18 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped
schepotkina [342]

Answer:  99% confidence interval would be (45.74,54.26).

Step-by-step explanation:

Since we have given that

N = 18

Mean = $50

Standard deviation = $7

At 99% confidence level, z = 2.58

So, Interval would be

\bar{x}\pm z\dfrac{\sigma}{\sqrt{n}}\\\\=50\pm 2.58\times \dfrac{7}{\sqrt{18}}\\\\=50\pm 4.26\\\\=(50-4.26,50+4.26)\\\\=(45.74,54.26)

Hence, 99% confidence interval would be (45.74,54.26).

8 0
4 years ago
Based on the drawing, Which can be used to prove PQR ≅ STV?
natta225 [31]

Answer:

Option (2) is correct.

Based on the drawing, SAS can be used to prove PQR ≅ STV

Step-by-step explanation:

We have to find the criterion by which the two given triangle can be prove similar from the given options.

Consider, the given triangles from the drawing given

ΔPQR and ΔSTV,

PR = VS  (Given)

∠QRP = ∠TVS ( Given)

and, QR = TV (given)

Thus,  PQR ≅ STV  ( SAS CRITERION)

For SAS criterion , we need to show that two sides and the angle between those sides are equal .

Thus, option (2) is correct.


5 0
4 years ago
A golf ball is hit with an initial velocity of 50 m/s at an angle of 45° above the horizontal. What's the maximum height it will
koban [17]
This problem is a projectile problem. The initial velocity is 50m/s at an optimum angle of 45. The maximum height or the height of the y component is at it's highest is asked. 

Informtion needed:
Acceleration due to gravity = 9.81m/s^2

Formula:

Hmax = ((V^2)(sin(angle))^2)/2g
Hmax = ((50^2)(sin45)^2)/(2*9.81) = 63.71 or letter B 63.5 m is the closest answer. 
7 0
4 years ago
100+100+100+100+100+100
Elis [28]

Answer:

600

Step-by-step explanation:

ez

7 0
3 years ago
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