3 years ago

Anybody tryna smash?

Mathematics

2 answers:

disa [49]3 years ago

5 0

Nooooooooooooooooooo

Nimfa-mama [501]3 years ago

3 0

Answer: fat bet

Step-by-step explanation:

You might be interested in

A cell phone plan costs $150 to start. Then there is a $25 charge each month.

grin007 [14]

Answer:

$175

Step-by-step explanation:

Since it’s only one month you just add 150 by 25

Correct me if I am wrong

7 0

3 years ago

Determine if the statement is always, sometimes, or never true. Two angles that are vertical are __________ adjacent.

Morgarella [4.7K]

Never true. Vertical angles are equal to each other, not adjacent to each other.

4 0

3 years ago

What is the area of the shaded region <br> 1cm is in the middle

Archy [21]

Answer:

Area of the shaded region= $128.86\,cm^2$

Step-by-step explanation:

Area of the shaded region=Area of the rectangle-Area of the circle

Area of rectangle= $Length\times Width$

$Length=11\,cm\\Width=12\,cm$

Area is:

$=11\times 12\\\\=132\,cm^2$

Area of the circle = $\pi \times r^2$

$r=1\,cm$

As, $\pi =\dfrac{22}{7} =3.14$

Area of the Circle is :

$=3.14\times 1 \times 1\\\\=3.14\times 1\\\\=3.14\,cm^2$

Area of the Shaded region:

Area of the shaded region $=132-3.14\\\\=128.86\,cm^2$

5 0

3 years ago

Find k so that 25x^2 + 40x + k is the square of the binomial.

allochka39001 [22]

K= 16

25x^2+40x+16x comes to be (5x+4)^2.

3 0

3 years ago

Read 2 more answers

A 2 kg metal cylinder is supplied with 1600J of energy to heat it from 5°C to 13°C. What is the specific heat capacity of the me

Neporo4naja [7]

Answer:

$c = 100\,\frac{J}{kg\cdot ^{\circ}C}$

Step-by-step explanation:

According to the First Law of Thermodynamics, the heat received by the metal cylinder is equal to the change in the internal energy. That is:

$Q = \Delta U$

$Q = m \cdot c \cdot \Delta T$

The specific heat is clear in the previous expression and finally computed:

$c = \frac{Q}{m\cdot \Delta T}$

$c = \frac{1600\,J}{(2\,kg)\cdot (13^{\circ}C-5^{\circ}C)}$

$c = 100\,\frac{J}{kg\cdot ^{\circ}C}$

6 0

3 years ago