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serious [3.7K]
2 years ago
7

Let S be a sample of size 31 from a normally distributed population Omega . It is given that the average of the data in S is 120

and the standard deviation is 18. Construct a 90% confidence interval [a, b] for the population mean based on the data in the sample.
Mathematics
1 answer:
Kipish [7]2 years ago
8 0

Answer:

48 NO seña hfjxsmisns sisbxbd

Step-by-step explanation:

<h2><em><u>nzhejsbxbddndbhwksdyanvxydjd4mnnnek</u></em><em><u>nwnennnnnn</u></em></h2>
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Solve for in the diagram below.
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X is 35. 180=75+3x. 180-75/3=35
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What is the area of the square below?
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Answer:

Step-by-step explanation:

32

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A sequence is defined by the recursive formula f(n+1)=f(n)-2. If f(1)=18, what is f(5)?
N76 [4]

Answer:

f(5)=10

Step-by-step explanation:

A sequence is defined by the recursive formula f(n+1)=f(n)-2

If f(1)=18, then

for n=1: f(2)=f(1+1)=f(1)-2=18-2=16

for n=2: f(3)=f(2+1)=f(2)-2=16-2=14

for n=3: f(4)=f(3+1)=f(3)-2=14-2=12

for n=4: f(5)=f(4+1)=f(4)-2=12-2=10

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3 years ago
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Please help!!! quick!! (brainliest if you get it right)
Evgesh-ka [11]
The correct answer is the fourth one
7 0
3 years ago
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3
Ierofanga [76]

Answer:

A

Step-by-step explanation:

Sum the product of the components in the first row of A with the corresponding components of the first column in B

Repeat this with the components in the second row of A with the corresponding components of the second column in B, that is

AB

= \left[\begin{array}{ccc}2&1\\3&4\\\end{array}\right] \left[\begin{array}{ccc}3&1\\5&2\\\end{array}\right]

= \left[\begin{array}{ccc}2(3)+1(5)&2(1)+1(2)\\3(3)+4(5)&3(1)+4(2)\\\end{array}\right]

= \left[\begin{array}{ccc}6+5&2+2\\9+20&3+8\\\end{array}\right]

= \left[\begin{array}{ccc}11&4\\29&11\\\end{array}\right]  → A

6 0
3 years ago
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