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serious [3.7K]
3 years ago
7

Let S be a sample of size 31 from a normally distributed population Omega . It is given that the average of the data in S is 120

and the standard deviation is 18. Construct a 90% confidence interval [a, b] for the population mean based on the data in the sample.
Mathematics
1 answer:
Kipish [7]3 years ago
8 0

Answer:

48 NO seña hfjxsmisns sisbxbd

Step-by-step explanation:

<h2><em><u>nzhejsbxbddndbhwksdyanvxydjd4mnnnek</u></em><em><u>nwnennnnnn</u></em></h2>
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Someone PLEASE HELP IF YOUR GOOD AT MATH
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Answer:

your answer is 33

Step-by-step explanation:

33×6=198

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What is a product of 10 and the counting numbers 1 2 3 and so on? Answer for 25 points!
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“four less than – 3.7 times a number is –11.9.”
Marysya12 [62]
-3.7n - 4 = -11.9
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3 years ago
You get a haircut that costs $23. You want to tip the barber 10%. How much tip will you leave him?
charle [14.2K]

Answer:

$2.30

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8 0
3 years ago
Read 2 more answers
What are the coordinates of R' for the dilation D(0.5. p)(PQRS)?
11111nata11111 [884]

Answer:

R' = (-1,-0.5)

Step-by-step explanation:

See attachment for complete question.

From the attachment:

P = (-3,-3)

R = (1,2)

Dilation:

D_{(0.5,P)}

Required

Determine R'

First, subtract the coordinates of P from R. This means that R is measured from P.

R = (1-(-3),2-(-3))

R = (1+3,2+3)

R = (4,5)

Next, apply dilation factor 0.5

R' = R * 0.5

R' = (4,5) * 0.5

R' = (4* 0.5,5* 0.5)

R' = (2,2.5)

Lastly, measure R' from the origin by adding the coordinates of P to R'

R' = (2+(-3),2.5+(-3))

R' = (2-3,2.5-3)

R' = (-1,-0.5)

6 0
2 years ago
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