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serious [3.7K]
3 years ago
7

Let S be a sample of size 31 from a normally distributed population Omega . It is given that the average of the data in S is 120

and the standard deviation is 18. Construct a 90% confidence interval [a, b] for the population mean based on the data in the sample.
Mathematics
1 answer:
Kipish [7]3 years ago
8 0

Answer:

48 NO seña hfjxsmisns sisbxbd

Step-by-step explanation:

<h2><em><u>nzhejsbxbddndbhwksdyanvxydjd4mnnnek</u></em><em><u>nwnennnnnn</u></em></h2>
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HELP me please! Please I really need it!
Crank

Answer:

The radius is 6.1 cm

Step-by-step explanation:

The volume of a sphere is

V = 4/3 pi r^3

There is a typo in the problem.

We know the volume

950 = 4/3 (3.14) r^3

Multiply each side by 3/4

3/4 *950 = 3.14 r^3

712.5 = 3.14 r^3

Divide each side by 3.14

712.5/3.14 = r^3

226.910828 = r^3

Take the cube root of each side

226.910828 ^ (1/3) = r^3 ^ 1/3

6.099371323 = r

The radius is 6.1 cm

4 0
3 years ago
HELP ASAPJennifer and Chris completed some chores and split the earnings in the ratio 3:2. Jennifer earned $48.
elixir [45]

Let the total earnings be = x

Jennifer and Chris split the earnings in the ratio 3:2

Jennifer earned = $48

\frac{3x}{5}=48

3x=240

x=80

Hence total earnings are $80

(a) Chris earning is = \frac{2x}{5}=\frac{2*80}{5}=32

Hence, Chris earns $32

(b) Jennifer spends 30% of her earnings on a book.

So, price of the book = \frac{30}{100}\times48

Price of book = $14.40

(c)  Jennifer also buys a magazine for = $5.40

So, total money Jennifer spent on book and magazine = 14.40+5.40=19.80

Money left with Jennifer = 48-19.80= $28.20

In fractions = \frac{28.20}{48}

or multiplying the numerator and denominator by 10, we get

\frac{282}{480}=\frac{47}{80}

(d) Let the original price of the shirt = x

reduction percentage on x= 40%

Price paid after reduction = 16.80

\frac{40x}{100}=16.80

40x=1680

x=42

Hence, the original price of the shirt was $42.


8 0
4 years ago
31-inch piece of steel is cut into three pieces so that the second piece is twice as long as the first piece and the third piece
pychu [463]

"31-inch piece of steel is cut into three pieces"

Call the pieces a,b,c

a + b + c = 31

"second piece is twice as long as the first piece"

b = 2a

"third piece is one inch more than seven times the length of the first piece"

c = 1 + 7a

Ok, we have our equations, let's substitute the second and third into the first.

a + 2a + 1 + 7a = 31

10a + 1 = 31

10a = 30

a = 30/10 = 3

b = 2a = 6

c = 1 + 7a = 22

Check: 3 + 6 + 22 = 31, good

Answer: 3 inches, 6 inches, 22 inches


4 0
3 years ago
Any help will mark brainliest
Lostsunrise [7]
4 x 2 tens = 80, 28 x 14 = 392
3 0
3 years ago
Which choice models this situation? Fahad needs to sell 25 tickets to a fundraiser by Friday. So far, he has sold 9 tickets. How
MrRa [10]

Answer:

16 tickets

Step-by-step explanation:

Number of tickets he has to sell = 25

Number of tickets he has sold = 9

How many tickets does he still need to sell?

Number of tickets he still needs to sell = Number of tickets he has to sell - Number of tickets he has sold

= 25 - 9

= 16 tickets

Number of tickets he still needs to sell = 16 tickets

Therefore, Fahad still needs to sell 16 more tickets

5 0
3 years ago
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