3 years ago

Help me pls I am struggling In everything

Mathematics

1 answer:

kotegsom [21]3 years ago

3 0

Answer:

The answers are A, B, C, F

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The temperature, T, of a given mass of gas varies inversely with its Volume,V. The temperature of 98 cm ³ of a certain gas is 28

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Answer:

T₂ = 421.4 K

Step-by-step explanation:

The temperature, T, of a given mass of gas varies inversely with its Volume,V.

$T\propto \dfrac{1}{V}\\\\V_1T_1=V_2T_2$

We have,

V₁ = 98 cm³, T₁ = 28° C = (28+273) K = 301 K

V₂ = 70 cm₃

We need to find the new temperature of the gas. Using the above relation to find T₂.

$T_2=\dfrac{V_1T_1}{V_2}\\\\T_2=\dfrac{98\times 301}{70}\\\\T_2=421.4\ K$

Hence, the required temperature of the gas is 421.4 K.

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Step-by-step explanation:

Multiply both sides by 12, Move constant to the right hand side and change its sign, Move variable to the left hand side and change its sign, collect like terms, divide both sides of the equation by -73, x=-63/73 (- 63 over 73)

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