Sum of n terms = a1 (r^n-1/ (r-1)
Sum of first one = 3 * (4^5 - 1) / 3 = 1023
.. 2nd = 5 * (6^2 - 1) / 5 = 35
.. 3rd = 5 ^4 - 1 / 4 = 156
.. 4th = 4 * (5^4 - 1) / 4 = 624
So in increasing order its 2nd, 3rd, 4th and first.
8 + 5 = 13
10 + 3 = 13
i think thats what you asking right
I think you clicked on the correct answer! Correct me if I’m wrong!
Answer:
Either A or D
Step-by-step explanation:
Because if you put the area of the two smaller squares together it would equal that one big square.
I don't know if this is right just a tough guess but I hope this helps!
And Good Job for almost being completed!
:)
Answer:
Subtract 11 from each number.
Step-by-step explanation:
-26,-37,-48,-59,-70,-81,-92,-103,-114,-125,-136,-147,-158,-169,-180
So on and so forth.
Hope this helps! Pls give brainliest!
