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Orlov [11]
3 years ago
10

Which of the following is the function representing the graph below? graph begins in the second quadrant near the x axis and inc

reases slowly while crossing the ordered pair 0, 1. When the graph enters the first quadrant, it begins to increase quickly throughout the graph.
Mathematics
1 answer:
Vadim26 [7]3 years ago
6 0
Your description corresponds to an exponential function.

So it is of the kind f(x) = A (e^kx)

Given that the pair (0,1) is in the graph, you can determine that A = 1:

1 = A (e ^ k*0)

=> 1 = A e^0

=> 1 = A

So, the function is of the kind f(x) = e^ (kx).

Where x is any positive value.

With that you can choose the right answer among your options.
You might be interested in
Please help me please
cupoosta [38]
Y = 925/z

hope this helps!

5 0
4 years ago
Loretta’s income last year was $81,300. She made $56,800 at her salaried job and had additional passive income. If Loretta earne
adell [148]

Answer:

The answer is $2041.67 approx.

Step-by-step explanation:

Loretta’s income last year was $81,300.

Amount made in salary = $56,800

So, additional passive income is = 81300-56800=24500 dollars

Given that Loretta earned the same amount of passive income each month for the entire year.

So, her per month passive earning was = \frac{24500}{12}=2041.67 dollars

Therefore, the answer is $2041.67 approx.

3 0
3 years ago
A chemist is using 351 millimeters of a solution of acid and water. If 18.2% of the solution is acid, how many milliliters of ac
Zolol [24]

Answer:

The % of of acid in solution  = 63.88 ml

Step-by-step explanation:

The solution of acid and water = 351 milliliters

The % of of acid in solution  = 18.2% of 351 ml

Or, The % of of acid in solution  = \frac{18.2}{100} × 351 ml

Or, The % of of acid in solution  = 63.882 ml

Hence ,The % of of acid in solution  = 63.88 ml  Answer

3 0
4 years ago
The sum of a number and its ??? equals 0
yarga [219]
Sum of the number and its of inverse equals 0.
a+(-a)=a-a=0
6 0
4 years ago
Help me idk how to do this
ElenaW [278]
To do this, you have to plug each x value into the rule.

1.y = 15 - 3×2
y = 15 - 6
y = 9

So the first y value would be 9.

2.y = 15 - 3×3
y = 15 - 9
y = 6

3. y = 15 - 3×4
y = 15-12
y = 3

4. y = 15 - 3×5
y = 15-15
y = 0

Hope this helps!

3 0
4 years ago
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