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3 years ago

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Solve the inequality. 4(p – 4) > 12 A. p 3 C. p > 16 D. p > 7 it would be nice if you can show me how you did step by s

tep

1 answer:

anzhelika [568]3 years ago

7 0

Answer:

D

Step-by-step explanation:

Given

4(p - 4) > 12 ( divide both sides by 4 )

p - 4 > 3 ( add 4 to both sides )

p > 7 → D

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(2 + 5i)(2 + i) <br><br> please help me to understand how to do it

Tpy6a [65]

<span>(2 + 5i)(2 + i)
= 4 + 10i + 2i + 5i^2
= 4 + 12i + 5i^2</span>

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3 years ago

A model of an airplane is 8 inches long. If the actual

andrew11 [14]

Answer:

The answer is

B.

Step-by-step explanation:

just multiply 4.5 by 8 and you get 36

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Identify the equation in slope-intercept form for the line that has the given slope and contains the given point. Slope = −1/2;

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First you need the equation y=mx+b
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3 years ago

A square plaza at a train station has a side length as

tekilochka [14]

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Step-by-step explanation:

2x+6

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3 years ago

Read 2 more answers

P and q are complex numbers such that ∣p∣ = 2/5 x + 2 , ∣q∣ = −3/4 x − 1 , and ∣p+q∣ = 2x + 4 .

Leya [2.2K]

Answer: (b)

Step-by-step explanation:

Given

$\left | p\right |=\dfrac{2}{5}x+2$

$\left | q\right |=\dfrac{-3}{4}x-1$

$\left | p+q\right |=2x+4$

for two complex number, $z_1,z_2$

$\left | z_1+z_2\right |\leq \left | z_1\right |+\left | z_2\right |$

Apply the above the property

$\Rightarrow 2x+4\leq \dfrac{2}{5}x+2-\dfrac{3}{4}x-1\\\\\Rightarrow 2x+4\leq \dfrac{8x-15x}{20}+1\\\\\Rightarrow 2x+3\leq -\dfrac{7x}{20}\\\Rightarrow x\leq -\dfrac{60}{47}$

Also, the absolute value of each complex number must be greater than or equal to zero

$\text{Case-1}\\\\\Rightarrow \dfrac{2}{5}x+2\geq 0\\\\\Rightarrow x\geq -5\\\\\text{Case-2}\\\\\Rightarrow -\dfrac{3}{4}x-1\geq 0\\\\\Rightarrow x\leq -\dfrac{4}{3}\\\\\text{Case-3}\\\\\Rightarrow 2x+4\geq 0\\\Rightarrow x\geq -2$

Taking the intersection of the above values of x, we get

$x\in [-2,-\dfrac{4}{3}]$

8 0

3 years ago