Answer:
45%
Step-by-step explanation:
Plugging -6 in for x, we get -2sqrt(-6-7+1)=sqrt(something negative) which is clearly not possible.
Plugging -6 in for f(x), we get -6=-2sqrt(x-7+1) and 3=sqrt(x-7+1). Squaring both sides, we get 9=x-7+1 and by adding both sides by 6 we get 15=x, therefore having (15,-6) and proving that -6 is in the range, but not the domain (B)
I think you meant to say

(as opposed to <em>x</em> approaching 2)
Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

Answer:
84
Step-by-step explanation:
Let the first digit = x
Let the second digit =y
x + y = 12
x + 4 = 3*y
===========
From the second equation, we learn that x = 3y - 4
Put that into the first equation.
3y - 4 + y = 12 Combine the left side
4y - 4 = 12 Add 4 to both sides
4y = 16 Divide by 4
4y/4 = 16/4
y = 4
=================
x + 4 = 12
x + 4 - 4 = 12-4
x = 8
So the number is 84