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Sergio039 [100]
3 years ago
9

Given that cosine theta = -1/2 and theta is obtuse find sin4theta

Mathematics
1 answer:
igomit [66]3 years ago
5 0

Answer:

0.8660

Step-by-step explanation:

cosine theta = -1/2

theta = cosinearctan(-0.5)

theta = 120

sine4theta = sine 4(120)

                   = sine480

                  = 0.8660

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3 years ago
2x+y=2 I am trying to solve that problem
posledela

Answer:

y= 2-2x

Step-by-step explanation:

Isolate y.

2x + y = 2 \\  y = 2 - 2x

4 0
3 years ago
The average Act score follows a normal distribution, with a mean of 21.1 and a standard deviation of 5.1. What is the probabilit
ohaa [14]

Answer:

0.43% probability that the mean IQ score of 50 randomly selected people will be more than 23

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

\mu = 21.1, \sigma = 5.1, n = 50, s = \frac{5.1}{\sqrt{50}} = 0.7212

What is the probability that the mean IQ score of 50 randomly selected people will be more than 23

This is 1 subtracted by the pvalue of Z when X = 23. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{23 - 21.1}{0.7212}

Z = 2.63

Z = 2.63 has a pvalue of 0.9957

1 - 0.9957 = 0.0043

0.43% probability that the mean IQ score of 50 randomly selected people will be more than 23

5 0
3 years ago
How i can answer this question
denis-greek [22]

Answer:

4k+11

Step-by-step explanation:

There you go. Happy to help.

4 0
2 years ago
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Aleksandr-060686 [28]

First we need to know how much the discount was so 5% is actually 0.05 then we need to multiply it by 53.75 which would equal 2.6875 then subtract it by 53.75 which would equal -51.0625.

B) .95(53.75)

This is a trick question because D) could also be correct if they said you could subtract it but it's not saying use the distributive property.

5 0
3 years ago
Read 2 more answers
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