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DedPeter [7]
2 years ago
12

What is the sum of (3q-2) (3q-2)?

Mathematics
1 answer:
alexandr1967 [171]2 years ago
3 0
FOIL
(9q^2)-(6q)-(6q)+4
9q^2 -12q +4
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PLZ HELP Word Problems on the system of equations:
ahrayia [7]

Answer:

let the two number be x and y then,

x+y=12

x-y=-4

-----------

2x=8

or, x = 4 put the value of x in first equation

4+y= 12

or, y=12-4

or, y= 8 hence the two number is 4 and 8

8 0
3 years ago
In rectangle ABCD, AB=8 units and BC=15 units. Find BD
BabaBlast [244]

Answer:


Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
24 - 1 / 3 p = 3 /8 p
Brums [2.3K]

Answer:

p=\frac{576}{17}

Step-by-step explanation:

decimal form p= 33.8823529411764705

mixed number form= 33\frac{15}{17}

6 0
3 years ago
david quiere saber cuanto requiere invertir mensualmente para obtener $30,760.08 durante 6 meses si los invierte con el 12% capi
Akimi4 [234]

Answer:

A = $32,652.44

Step-by-step explanation:

Given: Principal (P) = 30,760.08, Annual Rate (R) = 12%, Time (t in years) = 0.5

To find: How much David needs to invest monthly

Formula: A = P(1 + r/n)^n^t

Solution: To find, simply add principal + interest

First, convert R as a percent to r as a decimal

r = R/100

r = 12/100

r = 0.12 rate per year,

Then solve the equation for A

A = P(1 + r/n)nt

A = 30,760.08(1 + 0.12/12)(12)(0.5)

A = 30,760.08(1 + 0.01)(6)

A = $32,652.44

Therefore;  

The total amount David will obtain with 30,760.08 for 6 months, 12%is $32,652.44.

4 0
3 years ago
A local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle. In o
Eduardwww [97]

Answer:

(A)  H_0 : μ = 22 ; H_A : μ ≠ 22

(B) Value of the test statistic = -2.69

Step-by-step explanation:

We are given that a local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle. He takes a random sample of 65 bottles. The mean weight of the passion fruit juice in the sample is 21.54 ounces. Assume that the population standard deviation is 1.38 ounce.

We have to test the accuracy of the bottling process.

(A) Let, NULL HYPOTHESIS, H_0 : \mu = 22 ounces  {means that an average of 22 ounces of passion fruit juice is used to fill each bottle}

ALTERNATE HYPOTHESIS, H_A : \mu \neq 22 ounces  {means that an average of 22 ounces of passion fruit juice is used to fill each bottle}

The test statistics that will be used here is One-sample z-test;

             T.S. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample mean weight of the passion fruit juice = 21.54 ounces

            \sigma = population standard deviation = 1.38 ounces

            n = sample of bottles = 65

(B) So, <u>test statistics</u> =  \frac{21.54-22}{\frac{1.38}{\sqrt{65} } }

                                  = -2.69

Hence, the value of test statistics is -2.69.

6 0
3 years ago
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