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Fittoniya [83]
3 years ago
14

The two figures below are congruent. Find the measure of the angle that isn't labeled on either figure.

Mathematics
2 answers:
Katen [24]3 years ago
6 0
Step 1: Since this figure has 4 sides, the total degree will be 360 degrees.

Step 2: Create Equation: 41+86+133+x= 360

Step 3: Solve it: you will get the final answer of x=100
Anon25 [30]3 years ago
4 0

Answer:  The answer is 100°.

Step-by-step explanation:  We are given that the figures in the picture are congruent. Therefore, we will have

∠A = ∠J = 133°,

∠D = ∠M = 86°,

∠C = ∠L =41°.

We are to find the measurement of the fourth angle, which is ∠B or ∠K.

Since the figures are quadrilaterals, so the um of all the four angles must be 360°.

In quadrilateral ABCD, we have

\angle A+\angle B+\angle C+\angle D=360^\circ\\\\\Rightarrow 133^\circ+\angle B+41^\circ+86^\circ=360^\circ\\\\\Rightarrow 260^\circ+\angle B=360^\circ\\\\\Rightarrow \angle B=100^\circ.

Thus, the answer is ∠B = ∠K =100°.

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5a + s = 2662
a + s = 1198
4a = 1464
a = 366

5(366) + s = 2,662
1830 adult tickets sold

2662 - 1830 = 832
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3 years ago
Order the numbers from least to greatest.<br><br> 2.1,−610,−94,−0.75, 53
kirill115 [55]

Answer:

-610, -94, -0.75, 2.1, 53

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VMariaS [17]
The answer is d, when you divide 45 by 54 you get 0.833333333333.... the line above the 3 means that there is infinite number of threes
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Really need help guys!<br> Love you if you can solve them wiz steps!!!!
Marta_Voda [28]

Answer:

Step-by-step explanation:

x^2+y^2-8x+4y+4=0\\\\a)\\\\x^2-8x+y^2+4y+4=0\\\\x^2-2*x*4+(y^2+2*y*2+2^2)=0\\\\x^2-2*x*4+4^2+(y+2)^2=4^2\\\\(x-4)^2+(y+2)^2=4^2\\

Hence,

The radius of the circle is 4 units, coordinates of its centre are (4,-2).

b)\\\\y=0\\x^2+0^2-8x+4*0+4=0\\x^2-8x+4=0\\a=1\ \ \ \ b=-8\ \ \ \ c=4\\D=(-8)^2-4*1*4\\D=64-14\\D=48\\\sqrt{D}=\sqrt{48} \\ \sqrt{D}=\sqrt{16*3} \\\sqrt{D}=\sqrt{4^2*3}  \\\sqrt{D}=4\sqrt{3}  \\\displaystyle\\x=\frac{-(-8)б4\sqrt{3} }{2*1} \\\\x=\frac{8б4\sqrt{3} }{2} \\x_1=4-2\sqrt{3} \\x_2=4+2\sqrt{3}

c)\\\\A(6,2\sqrt{3}-2)\\ (x-4)^2+(y+2)^2=4^2\\(6-4)^2+(2\sqrt{3} -2+2)^2=16\\2^2+(2\sqrt{3} )^2=16\\4+2^2*(\sqrt{3})^2=16\\ 4+4*3=16\\4+12=16\\16\equiv16

d)\\A(6,2\sqrt{3}-2)}\\\sqrt{3} x+3y=\\\sqrt{3}(6)+3(2\sqrt{3} -2)=\\ 6\sqrt{3}+6\sqrt{3} -6=\\ 12\sqrt{3}-6

5 0
1 year ago
Consider the diagram below. Which of the following statements are correct? Select all that apply. (Diagram and answer options ar
Vika [28.1K]

Answer:

Options 1,2,6,7 are correct statements.

Step-by-step explanation:

In the given figure lines m and n are cut by a transversal t.

Among all the statements the options that are correct are :

1)<1 and <5 are corresponding angles.(The angles in matching corners are called corresponding angles)

2)<3 and <6 are alternate interior angles .(The angles that are formed on opposite sides of the transversal and inside the two lines are alternate interior angles)

6)<4 and <6 are same side consecutive angles.(consecutive angles lie on the same side of the transversal)

7)<1 and <8 are alternate exterior angles.( These angles lie on the exterior side of the lines and on opposite side of the transversal)

3 0
3 years ago
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