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KATRIN_1 [288]
3 years ago
6

What is 12x3 – 9x2 – 4x + 3 in factored form?

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
5 0
The answer is (4x-3)(3x^2-1)
serg [7]3 years ago
5 0

Answer:

(3x^2 - 1) (4x-3)

Step-by-step explanation:

Edgenuity.

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Answer: Dilation is a technique for creating similar figures. Each point is stretched outwards from the center point D by multiplying distances by the scale factor. (Outwards if the scale factor is bigger than 1.) Move the points A, B, and C to change the shape of the triangle.

Step-by-step explanation:

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What is the GCF of h4 and 18?<br> Oh2<br> Oh4<br> O 18<br> O 12
stich3 [128]

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Step-by-step explanation:

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3 years ago
Read 2 more answers
Help i dont understand this
Igoryamba
I’m not extremely good at math but I think you need to make -x-y=1 into y=mx+b form and then solve your new equation!
4 0
3 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
Find the simplified product. 2V5x^3(-3/10x^2)
mariarad [96]

Answer:

Step-by-step explanation:

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3 years ago
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