Im not quite sure but i think the unit rate is 150. Hope this helps!!
Answer:
A: 6
B: 16
C: 2
D: -12
Step-by-step explanation:
They are asking you to multiply the equations:
(3x^2 + 2x - 3)(2x + 4)
Distribute and you should get:
6x^3 + 16x^2 + 2x - 12
The Coefficients A,B,C, and D are 6, 16, 2, and -12.
I see your last line is : c(x) = 0.9(x^2-10)^2 + 101.1
Let y = x^2, then c(y) = 0.9(y-10)^2 + 101.1
Apparently, c(y) is a parabola, min is 101.1 when y = 10, max is infinity
So let x^2 = 10 -> x = sqrt(10) or -sqrt(10), min is 101.1, max is infinity
Answer:
The distance between the two train stations is 1728 km
Step-by-step explanation:
The speed of the bus = 54 km/h
The speed of the truck = 48 km/h
When the bus and truck meet again, the distance covered by the bus = 216 km more than he distance traveled by the truck
Let the distance between the two train stations = x
Let the location where they first meet be y from station A we have;
The location where they meet again = y - 216 km
Therefore, we have;
Location where they
The time for the truck and the bus to meet again = t
Therefore, 54 × t - 48 × t = 216 km
6·t = 216 km
t = 36 hours
Therefore, the time for the bus to travel x + 216 km = 36 hours
54 × 36 = 1944 = x + 216
x = 1944 - 216 = 1728 km
The distance between the two train stations = 1728 km.
Answer:
15
Step-by-step explanation:
5(2)(3)-2(2)+13+7(2)-6(2)(3)-4(2)+(2)(3)
30-4+13+14-36-8+6
15
