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3 years ago

Help 35 points Which value of c markes

Mathematics

2 answers:

miskamm [114]3 years ago

7 0

X=6 because 6-3 is 3 then which makes 3/4 . 3/4 also equals 9/12 plus 2/3 (which equals 8/12) is 17/12

sveticcg [70]3 years ago

3 0

Answer:

x=6 Isolate the variable by dividing each side by factors that don't contain the variable.

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zzz [600]

Answer:

Step-by-step explanation:

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5 0

2 years ago

Read 2 more answers

Distribute (x-6)(x-7) a) x^2-13x-15 b) x^2-13x+42 c) x^2+x+42 d) x^2+x-15

Sidana [21]

Answer:

B. x² - 13x + 42

Step-by-step explanation:

7 0

2 years ago

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Lynna [10]

Answer:

write 16 in the soup column and 27 in the peanut butter column

6 0

3 years ago

Which of these problem types can not be solved using the Law of Sines?

andrezito [222]

I think the answer is B!

Hope this helps

6 0

3 years ago

Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim

Ber [7]

The given function is

$f(x)=4\cos \text{(}\pi x)+1$

The general form of the cosine function is

$y=a\cos (bx+c)+d$

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

$\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}$

The equation of the midline is

$y_{ml}=\frac{y_{\max }+y_{\min }}{2}$

Since the maximum is at the greatest value of cos, which is 1, then

$\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}$

Since the minimum is at the smallest value of cos, which is -1, then

$\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}$

Then substitute them in the equation of the midline

$\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}$

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0

10 months ago