To get the inverse "relation" of an expression, we first off, do a quick switcharoo of the variables, and then solve for "y", so let's proceed,

$\bf x^2+y^2=4\qquad inverse\implies \boxed{y}^2+\boxed{x}^2=4
\\\\\\
y^2=4-x^2\implies y=\pm\sqrt{4-x^2}$

and yes, the domain for the range 0 ⩽ x <span>⩽ 2, let's get instead the "range" of the original function,

</span> $\bf x^2+y^2=4\implies 0^2+y^2=4\implies y=\pm\sqrt{4}\implies \boxed{y=\pm 2}
\\\\\\
x^2+y^2=4\implies 2^2+y^2=4\implies 4+y^2=4\implies \boxed{y=0}\\\\
-------------------------------\\\\
\stackrel{\textit{range of original}}{-2\le y \le 2}~~=~~\stackrel{\textit{domain of its inverse}}{-2\le x \le 2}$ <span>
</span>

8 0

3 years ago

If one side of a square notebook measures 20 cm, what is the area of the front cover of the notebook?

nexus9112 [7]

Answer:

400cm

Step-by-step explanation:

8 0

2 years ago

EXPERTS HELP!! Jane was playing a game with her sister, Sally. Jane was down by 7. After her next turn, she was down by 3. Which

max2010maxim [7]

............Te he answer is C