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neonofarm [45]
3 years ago
11

Kendra and her horse completed the barrel racing course in 15.839 seconds. what is the number rounded to the nearest tenths? exp

lain how you decide.
Mathematics
1 answer:
Illusion [34]3 years ago
3 0
Please answer please please thank you thank
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all unicorns on rainbow island are either green or yellow. every time the clock strikes midnight the unicorns change their color
Oksi-84 [34.3K]

77 unicorns, because yesterday the ratio was 6:5 and today it is 3:4. If you add the numbers for both ratios together, you get 11 and 7. Finding the LCM of these two gives 77 (because 7 and 11 are both prime).

You find the LCM of the sums because when you find values based on ratios, you divide value by the sum of the ratio.

e.g. I have 100 fruits. The ratio of apples to oranges is 2:3. How many apples are there?

To solve this you'd add 2 and 3 (5), divide 100 by 5 (20), multiply that by 2 (40) because that's the ratio of apples to oranges.

In this case, you do the reverse. So If I have 77 unicorns, then yesterday there were (77/11 = 7, 7*6= 42, 7*5= 35) 42 green unicorns and 35 yellow. The sum of 42 and 35 is 77. If you do this process with the other ratio you'll get similar results as well.

6 0
3 years ago
Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n
Mazyrski [523]

We can use the fact that, for |x|,

\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n

Notice that

\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1{1-x}\right]=\dfrac1{(1-x)^2}

so that

f(x)=\displaystyle\frac5{(1-x)^2}=5\frac{\mathrm d}{\mathrm dx}\left[\sum_{n=0}^\infty x^n\right]

f(x)=\displaystyle5\sum_{n=0}^\infty nx^{n-1}

f(x)=\displaystyle5\sum_{n=1}^\infty nx^{n-1}

f(x)=\displaystyle5\sum_{n=0}^\infty(n+1)x^n

By the ratio test, this series converges if

\displaystyle\lim_{n\to\infty}\left|\frac{(n+2)x^{n+1}}{(n+1)x^n}\right|=|x|\lim_{n\to\infty}\frac{n+2}{n+1}=|x|

so the series has radius of convergence R=1.

5 0
3 years ago
A bug completes one lap along the edge of a circular planter of radius 11.7 cm in 13.91 s. How fast was it traveling? 1. 10.8518
IrinaK [193]

Answer:

8.5.28492 cm/s

Step-by-step explanation:

We are given that

Radius of circular planter=11.7 cm

Time taken by bug =13.91 s

We have to find the speed of bug.

We know that

Speed =\frac{distance}{time}

Distance traveled by bug =2\pi r

Distance traveled by bug =2\times 3.14\times 11.7

Because \pi=3.14

Speed of bug=\frac{2\times 3.14\times 11.7}{13.91}=5.28224 cm/s

Hence, speed of bug=5.2822 4 cm/s

Answer:8.5.28492 cm/s

8 0
3 years ago
PLEASE HELP ME<br> QUICK PLEEEEAAASE
sasho [114]

Answer:

A 2/6 and 3/6 is the Answer

7 0
3 years ago
Read 2 more answers
Does anybody know the answer to this? (Also could I give the link to someone so they could help with the rest?)
Vesnalui [34]

Answer:

2x+168=166

2x= -2

x=-2

LMT= 94

Step-by-step explanation:

8 0
3 years ago
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