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1 year ago

Find the surface area

Mathematics

2 answers:

svet-max [94.6K]1 year ago

7 0

Answer

Step-by-step explanation:

NARA [144]1 year ago

3 0

Answer:

96m

Step-by-step explanation:

Surface area of a pyramids formula is SA= B+1/2*l*P

B= area of base

l= slant height

P= perimeter of base

B= 6*6= 36

l= 5

P= 6+6+6+6 = 12+12 = 24

plug them into the formula

SA= (36)+1/2 * (5)*(24)

SA = (36)+1/2* 120 ------------- do 5 * 24

SA= (36) + 60 -----------do 120/2

SA = 96

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Answer:

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2 years ago

Brainly the owner of a hat store buys a hat for 5.50 he uses a markup rate up 105% what is the sale price of the hat

nirvana33 [79]

11.275 is the sale price of the hat

Step-by-step explanation:

Brainly the owner of a hat store buys a hat for 5.50 and he uses a mark-up rate is 105%. Need to find out what is the sale price of the hat.

Here, given data, cost price of hat = 5.5. Let the selling price of hat be x and find the data as asked in question,

$\text {Markup rate}=\frac{S . P .-C . P .}{S . P .} \times 100$

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Suppose small aircraft arrive at a certain airport according to a Poisson process with rate a 5 8 per hour, so that the number o

timurjin [86]

Answer:

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(b) The expected value of the number of small aircraft that arrive during a 90-min period is 12 and standard deviation is 3.464.

Step-by-step explanation:

Let the random variable X = number of aircraft arrive at a certain airport during 1-hour period.

The arrival rate is, λt = 8 per hour.

(a)

For t = 1 the average number of aircraft arrival is:

$\lambda t=8\times 1=8$

The probability distribution of a Poisson distribution is:

$P(X=x)=\frac{e^{-8}(8)^{x}}{x!}$

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Thus, the probability that exactly 6 small aircraft arrive during a 1-hour period is 0.12214.

Compute the value of P (X ≥ 6) as follows:

$P(X\geq 6)=1-P(X$

Thus, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8088.

Compute the value of P (X ≥ 10) as follows:

$P(X\geq 10)=1-P(X$

Thus, the probability that at least 10 small aircraft arrive during a 1-hour period is 0.2834.

(b)

For t = 90 minutes = 1.5 hour, the value of λ, the average number of aircraft arrival is:

$\lambda t=8\times 1.5=12$

The expected value of the number of small aircraft that arrive during a 90-min period is 12.

The standard deviation is:

$SD=\sqrt{\lambda t}=\sqrt{12}=3.464$

The standard deviation of the number of small aircraft that arrive during a 90-min period is 3.464.

(c)

For t = 2.5 the value of λ, the average number of aircraft arrival is:

$\lambda t=8\times 2.5=20$

Compute the value of P (X ≥ 20) as follows:

$P(X\geq 20)=1-P(X$

Thus, the probability that at least 20 small aircraft arrive during a 2.5-hour period is 0.5298.

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$P(X\leq 10)=\sum\limits^{10}_{x=0}(\frac{e^{-20}(20)^{x}}{x!})\\=0.01081\\\approx0.0108$

Thus, the probability that at most 10 small aircraft arrive during a 2.5-hour period is 0.0108.

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