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kow [346]
4 years ago
5

F(x)=6x^2 +10x−1

Mathematics
1 answer:
KATRIN_1 [288]4 years ago
3 0

Answer: It has two distinct real zeros.

Step-by-step explanation:

The formula that is used to calculate the discriminant of a Quadratic function is the one shown below:

D=b^2-4ac

In this case you have the following Quadractic function provided in the exercise:

f(x)=6x^2 +10x-1

Let's make it equal to 0:

0=6x^2 +10x-1

You can identify that:

a=6\\\\b=10

Knowing these values, you can substitute them into the formula and then evaluate:

D=10^2-4(6)(-1)\\\\D=124

Therefore, since:

 D>0

You can determine that the it has two distinct real roots.

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