Question

F(x)=6x^2 +10x−1

Answer 1

Answer: It has two distinct real zeros.

Step-by-step explanation:

The formula that is used to calculate the discriminant of a Quadratic function is the one shown below:

$D=b^2-4ac$

In this case you have the following Quadractic function provided in the exercise:

$f(x)=6x^2 +10x-1$

Let's make it equal to 0:

$0=6x^2 +10x-1$

You can identify that:

$a=6\\\\b=10$

Knowing these values, you can substitute them into the formula and then evaluate:

$D=10^2-4(6)(-1)\\\\D=124$

Therefore, since:

 $D>0$

You can determine that the it has two distinct real roots.