Answer:
The equation is 4 1/3(2/5+1)
Step-by-step explanation:
So, it's 4 1/3+1 11/15=
65/15+26/15=91/15
6 1/15
2/5x4 1/3
Which is 2/5 x 13/3
Which is 26/15
Which is 1 11/5
Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
You add 8 and 5 so the equation would be 8+5=13
Answer:
∠1 = 72°
Step-by-step explanation:
Complementary angles sum to 90°, thus
∠1 + ∠2 = 90, substitute ∠1 = 4∠2 , thus
4∠2 + ∠2 = 90
5∠2 = 90 ( divide both sides by 5 )
∠2 = 18°
Hence ∠1 = 90 - 18 = 72°