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sammy [17]
4 years ago
5

Which of the following is commonly used as a sacrificial metal?

Chemistry
1 answer:
Phoenix [80]4 years ago
3 0

Answer:

A

Explanation:

Magnesium.

Magnesium, Zinc and Aluminium are called as Sacrificial Anodes.

They are relatively pure active metals.

the sacrificial anode works by introducing another metal surface with a more negative electronegative and much more anodic surface.

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The flocculation basin often has a number of compartments with decreasing mixing speeds as the water advances through the basin. ... This compartmentalized chamber allows increasingly larger floes to form without being broken apart by the mixing blades.

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What is the difference between the low tide and the high tide
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Which image exclusively represents the principle of radiation? A) IV B) III C) II D) I
arsen [322]

The principle of radiation protection is to trigger deterministic and stochastic effect.

Explanation:

The main aim of principle of radiation is to prevent the deterministic effects of radiation and reduce the risks of stochastic effects.

There are three general principals of radiation used for dealing with ionising radiation are Justification, Dose limitation and Optimization.

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3 years ago
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If the atomic number of an element is 8 and the mass number is 16, the number of neutrons in an atom of that element is what? (s
Serjik [45]

Answer:

8.

Explanation:

Atomic number tells us the number of protons in an element. Mass number is the total amount of mass in an atom, and it comes from the sum of the mass of protons and neutrons, which are both considered to have a mass of 1 amu.

If the total mass is 16amu and 8amu comes from the 8 protons, the remaining mass comes from neutrons.

16 - 8 = 8

5 0
3 years ago
Cerium (IV) ions are strong oxidizing agents in acid ic solution, oxidizing arsenio us acid to arsen ic acid accor ding to the f
kirill [66]

Answer:

0.2042 M is the original concentration of Ce^{4+} (aq) in the titrating solution.

Explanation:

Mass of As_2O_3 = 0.217 g

Moles of As_2O_3=\frac{0.217 g}{198 g/mol}=0.001096 mol

1 mole of As_2O_3 have 2 mole of As  and 1 mole of H_3AsO_3 have 1 mole of As.

So, from 1 mole of As_2O_3 we will have 2 moles of H_3AsO_3

Then from 0.001096 mol of As_2O_3 :

2\times 0.001096 mol=0.002192 mol of H_3AsO_3

2Ce^{4+}(aq)+H_3AsO_3(aq)+3H_2O(l)\rightarrow 2Ce^{3+}(aq)+H_3AsO_4(aq)+2H^+(aq)

According to reaction, 1 mole of H_3AsO_3 reacts with 2 mole of cerium (IV) ions,then 0.002192 mol of

\frac{2}{1}\times 0.002192 mol=0.004384 mol of cerium (IV) ions.

Volume of the  acidic cerium{IV) sulfate = 21.47 ml =0.02147 L

1 mL = 0.001 L

concentration = \frac{Moles}{Volume(L)}

[Ce^{4+}]=\frac{0.004384 mol}{0.02147 L}=0.2042 M

0.2042 M is the original concentration of Ce^{4+} (aq) in the titrating solution.

8 0
3 years ago
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