All categories

3 years ago

Which of the following is commonly used as a sacrificial metal?

Chemistry

1 answer:

Phoenix [80]3 years ago

3 0

Answer:

Explanation:

Magnesium.

Magnesium, Zinc and Aluminium are called as Sacrificial Anodes.

They are relatively pure active metals.

the sacrificial anode works by introducing another metal surface with a more negative electronegative and much more anodic surface.

You might be interested in

PLEASE HELP!!!!

coldgirl [10]

Answer:

1.2 liters.

Explanation:

Focus on the 4th digit: that's the ones column. The 3rd digit is the decimal place, just be sure to round up.

7 0

3 years ago

A forensic scientist reports that a dead woman had high concentrations of a pain-fighting drug in her blood. What type of analys

AlladinOne [14]

C) the scientist made an identification by identifying the amount of drug in her blood and realising it was high

3 0

3 years ago

Read 2 more answers

The combustion of palmitic acid is represented by the chemical equation: C16H32O2(s) + 23O2(g) → 16 CO2(g) + 16 H2O(l) The magni

solniwko [45]

Answer:

The correct option is C

Explanation:

From the question we are told that

The reaction is

$C_{16}H_{32}O_2(g) + 23O_2(g) \to 16 CO_2(g) + 16 H_2O(l)$

Generally $\Delta H = \Delta U + \Delta N* RT$

Here $\Delta H$ is the change in enthalpy

$\Delta U$ is the change in the internal energy

$\Delta N$ is the difference between that number of moles of product and the number of moles of reactant

Looking at the reaction we can discover that the elements that was consumed and the element that was formed is $O_2$ and $CO_2$ and this are both gases so the change would occur in the number of moles

$\Delta H = \Delta U + [16 -23]* RT$

$\Delta H = \Delta U -7RT$

The negative sign in the equation tell us that the enthalpy $\Delta_r H$ would be less than the Internal energy $\Delta_r U$

4 0

3 years ago

If a gas has a proportionality constant of 4.32 x 10-4 mol at room temperature for a particular solvent, what will the

inysia [295]

$0.0467 X 10^{-4} M/kPa$ is the solubility of the gas when it exerts a partial pressure of 92.4kPa.

<h3>What is Henry's law?</h3>

Mathematically, we can get this from Henry's law

From Henry law;

Concentration = Henry constant × partial pressure

Thus Henry constant = $\frac{Concentration}{partial \;pressure}$

Henry constant = $\frac{4.32 \;X \;10^{-4} mol}{92.4kPa}$

$= 0.0467 X 10^{-4} M/kPa$

Hence, $0.0467 X 10^{-4} M/kPa$ is the solubility of the gas when it exerts a partial pressure of 92.4kPa.

Learn more about the Henry's law here:

brainly.com/question/16222358

#SPJ1

6 0

2 years ago

A metallurgical firm wishes to dispose of 1200 gallons of waste sulfuric acid whose molarity is 1.05 M. Before disposal, it will

Reil [10]

Answer:

The balanced chemical equation for this process:

$H_2SO_4(aq)+Ca(OH)_2(s)\rightarrow 2H_2O(l)+CaSO_4(aq)$

$194.51 is the cost that the firm will incur from this use of slaked lime.

Explanation:

The balanced chemical equation for this process

$H_2SO_4(aq)+Ca(OH)_2(s)\rightarrow 2H_2O(l)+CaSO_4(aq)$

Moles of sulfuric acid = n

Volume of sulfuric acid disposed = V = 1200 gallons = 3.785 × 1200 L = 4,542 L

1 gallon = 3.785 Liter

Morality of the sulfuric acid = M = 1.05 m

$Molarity(M)=\frac{n}{V(L)}$

$n=m\times V=1.05 M\times 4,542 L=4,769.1 mol$

According to reaction, 1 mol of sulfuric acid reacts with 1 mole of calcium hydroxide.Then 4,769.1 moles of sulfuric acid will recat with ;

$\frac{1}{1}\times 4,769.1 mol=4,769.1 mol$ of calcium hydroxide

Mass of 4,769.1 moles of calcium hydroxide:

4,769.1 mol 74 g/mol = 352,913.4 g

= $\frac{352,913.4 }{453.6} pounds =778.03 pounds$

(1 pound = 453.6 grams)

Cost of 1 pound of slaked lime = $0.25

Cost of 778.03 pounds of slaked lime = $0.25 × 778.03 = $194.51

$194.51 is the cost that the firm will incur from this use of slaked lime.

3 0

3 years ago