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son4ous [18]
4 years ago
5

Write a balanced chemical equation for each of the following

Chemistry
1 answer:
stellarik [79]4 years ago
4 0
1.) MgO + Fe --> FeO + Mg
2.) H + I --> HI
3.) Na + I --> NaI
4.) NaO + H2O --> NaOH + H
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What is the result of multiplying 2.5 times 10 to the power 10 by 3.5×10 to the power of -7
AURORKA [14]

Answer:

8.75 × 10³

Explanation:

Multiply the coefficients and the exponential terms separately; then multiply them together

2.5 × 3.5 = 8.75.

When you multiply exponential terms, you add the exponents.

10¹⁰ × 10⁻⁷ = 10⁽¹⁰⁻⁷⁾ = 10³

The product is 8.75 × 10³.

A scientific calculator does the operation automatically. The buttons may have different labels on your calculator, but the key sequence is usually something like

2.5 Exp 10 × 8.5 Exp +/- 7 = 8.75×10⁻³

6 0
3 years ago
A 33.6 mL solution of KCl has a mass of 27.29 g. After evaporating to dryness, the dry salt residues has a mass of 6.31 g. Calcu
bixtya [17]

For  the molarity and the  percentage of the mass of kcl are mathematically given as

%m/m = 23.1%, molarity  = 3.38M

<h3>What is the molarity?</h3>

Generally, the equation for the  percentage of the mass of kcl is mathematically given as

(mass of kcl/mass of solution)x 100

therefore

%m/m = (6.31/27.29)x100

%m/m = 23.1%

The molarity

(no of mol/ vol of sol)

molarity  = 0.0846mol/0.0250 L

molarity  = 3.38M

In conclusion, the molarity is given as

molarity  = 3.38M

Read more about Molarity

brainly.com/question/9149034

4 0
2 years ago
BRAINLIESTTT ASAP!! PLEASE HELP ME :)
deff fn [24]

Answer:

True

Explanation:

There are two types of Van der waals forces which are intermolecular bonds. These bonds are London dispersion forces and Dipole-dipole attractions.

The london dispersion forces are weak attractions found between non-polar molecues and noble gas.

The attractions here is as a result of the fact that non-polar molecules or atoms sometimes becomes polar because the constant motion of its electrons may lead to an uneven charge distribution at an instant. This leads to the formation of a temporary dipole or instantaneous dipole. The dipole can induce the neighbouring molecules to be distorted and they form dipoles as well.

7 0
4 years ago
Read 2 more answers
Compared to 1 liter aqueous solution with a ph of 7, a 1 liter aqueous solution with a ph of 5.0 contains
Annette [7]
Each unit of pH represents a change by a factor of 10. Thus in a pH of 5, there would be 100x the concentration of Hydrogen ions in solution.

The correct option would be 2.
6 0
3 years ago
What is the concentration of NaCl in a solution if titration of 15.00 mL of the solution with 0.2503 M AgNO3 requires 20.22 mL o
Nina [5.8K]

Answer:

The concentration of NaCl = 0.3374 M

Explanation:

Given :

Molarity of AgNO₃ = 0.2503 M

Volume of AgNO₃ = 20.22 mL

The conversion of mL into L is shown below:

1 mL= 10^{-3} L

Thus, volume of the solution = 20.22×10⁻³ L

Molarity of a solution is the number of moles of solute present in 1 L of the solution.

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

The formula can be written for the calculation of moles as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Thus,  

Moles\ of\ AgNO_3 =Molarity \times {Volume\ of\ the\ solution}

Moles\ of\ AgNO_3 =0.2503 \times {20.22\times 10^{-3}}\ moles

Moles\ of\ AgNO_3 = 5.0611 \times 10^{-3} moles

The chemical reaction taking place:

AgNO_3_(aq) + NaCl_(aq) \rightarrow AgCl_(s) + NaNO_3_(aq)

According to reaction stoichiometry:

<u>1 mole</u> of AgNO₃ reacts with <u>1 mole</u> of NaCl

Thus,

5.0611×10⁻³ moles of AgNO₃ reacts with 5.0611×10⁻³ moles of NaCl

Thus, moles of NaCl required = 5.0611×10⁻³ moles

Volume of NaCl required = 15.00 mL

The conversion of mL into L is shown below:

1 mL= 10^{-3} L

Thus, volume of the solution = 15.00×10⁻³ L

Applying in the formula of molarity as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity\ of\ NaCl=\frac{5.0611\times 10^{-3}}{15.00\times 10^{-3}}

Molarity\ of\ NaCl= 0.3374 M

<u>Thus, the concentration of NaCl = 0.3374 M</u>

6 0
3 years ago
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