Answer:
AsF3:C2CI6
4:3
1.3618 moles: 1.02135 moles(1.3618÷4×3)
C2CI6 is the limting reagent
So the number of moles for AsCI3 is 0.817 moles( number of moles of the limting reagant) ÷3 ×4 (according to ratio by balancing chemical equation)=1.09 moles(3 s.f.)
or
Balanced equation
4AsF3 + 3C2Cl6 → 4AsCl3 + 3C2Cl2F4
Use stoichiometry to calculate the moles of AsCl3 that can be produced by each reactant.
Multiply the moles of each reactant by the mole ratio between it and AsCl3 in the balanced equation, so that the moles of the reactant cancel, leaving moles of AsCl3.
Explanation:
Answer:
AlF₃ is Lewis Acid
CH₃F is Lewis Base
Explanation:
According to Lewis concept ,"those compounds which donate pair of electrons are called as Lewis Base and those accepting pair of electrons are called as Lewis Acid.
In Given Reaction,
<span> AlF</span>₃<span> + CH</span>₃<span>F → CH</span>₃⁺<span> + [AlF</span>₄<span>]</span>⁻
AlF₃ is acting as acid because the octet of Al is not complete, hence it has tendency to accept electrons.
CH₃F is acting as a base because the F atom containing three lone pair of electrons can donate it to Al metal resulting in the formation of electrophile i.e. CH₃⁺.
Answer:
if you will decrease the HCO3- so the less H+ ion will be form and reaction will more likely shift to product and when HCO3- decreases pH value increases and vica versa for the increasing HCO3 the more H+ ion will be form and reaction will shift to product and the pH value will decreases!!
I've doubt in reaction shift coz whatever is the amount of HCO3- this is completely gonna form number of H+ so reaction shift may or may not be same!!
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Explanation:
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<span>Atomic number and mass number for the carbon isotope with seven neutrons are:
Z,A = 6,13
There are 3 isotopes of carbon that are carbon 12, carbon 13 and carbon 14.
The carbon atom with seven neutron is carbon 13. Each carbon has 6 protons so its atomic number is 6 and when it has seven neutron then mass number will be (6 + 7) = 13
So, atomic number Z is 6 and mass number A is 13.</span>
