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Luda [366]
3 years ago
12

If a black ball is denser than a white ball of the same size, what does the black ball have??

Chemistry
1 answer:
yKpoI14uk [10]3 years ago
7 0

Answer: The black ball will have more mass than the white ball.

Explanation: Density of a substance is defined as the ratio of mass and volume occupied by the substance.

Mathematically,

Density=\frac{Mass}{Volume}

We are given that the two balls are of same size, which means that the volume of both the balls are same. We are also given that the black ball is more dense than the white ball, which means that the black ball will have more mass.

As, Density\propto Mass

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Write balanced equations for all the reactions in the catabolism of glucose to two molecules of glyceraldehyde 3-phosphate (the
Reil [10]

Solution :

The balanced chemical equation are

The Catabolism of the glucose takes place in five stages :

1. Glucose + $ATP$ → glucose - $6$ - phosphate $+ ADP$  ,  $\Delta G^0=-16.7 \ kJ/mol$

2. Glucose - $6$ - phosphate → Fructose - $6$ - phosphate ,  $\Delta G^0=1.7 \ kJ/mol$

3. Glucose - $6$ - phosphate + $ATP$ → $ADP$ + Fructose - $1,6- \text{biophosphate}$,  $\Delta G^0=-14.2 \ kJ/mol$

4. Fructose - $1,6- \text{biophosphate}$  → dihydroxyacetonephosphate + glyceraldehyde  $-3 - $ phosphate,   $\Delta G^0=23.8 \ kJ/mol$

5. Dihydroxyacetonephosphate → glyceraldehyde  $-3 - $ phosphate , $\Delta G^0=7.5 \ kJ/mol$

Therefore, the overall net equations

Glucose + $2ATP \rightarrow$ glyceraldehyde  $-3 - $ phosphate + $2ADP$ $\Delta G^0=2.1 \ kJ/mol$

5 0
3 years ago
How many moles of gas are in a volume of 44.4L at STP? n=.......mol
aniked [119]
You have to use the molar volume of gas which is 22.4L/mol at STP.  To find the number of moles of from a given volume of gas at STP, you need to divide the given volume by 22.4L/mol.
44.4L/22.4L/mol=1.98mol of gas
5 0
4 years ago
Calculate the number of molecules present in 3.50 mol feo2. 2.11 x 1024 molecules 2.107 x 1023 molecules 3.50 x 1023 molecules
elena-14-01-66 [18.8K]

Calculate the number of molecules present in 3.50 mol feo2. 2.11 x 1024 molecules 2.107 x 1023 molecules 3.50 x 1023 molecules <u>3.5*(6.02*10^23)=2.107*10^24 molecules</u>

<h3>What is molecules?</h3>

A molecule is the smallest unit of a substance that keeps its content and properties. It is made up of two or more atoms that are joined together by chemical bonds. Chemistry is built on molecules. The element symbol and a subscript indicating the number of atoms are used to identify molecules.

The fundamental building block of an element is an atom. They are made up of an electron-surrounded nucleus. An atom is considered to have valence electrons if its electron shell is not completely complete. A chemical (covalent) connection is created and a lower energy state is entered when two or more atoms join forces to share outer shell valence electrons. In an exothermic reaction, energy is released as atoms bond.

To learn more about molecules from the given link:

brainly.com/question/24722507

#SPJ4

6 0
2 years ago
A certain liquid X has a normal freezing point of 7.60 °C and a freezing point depression constant K= 6.90 °C-kg-mol. Calculate
Dmitry [639]

<u>Answer:</u> The freezing point of solution is -5.11°C

<u>Explanation:</u>

Vant hoff factor for ionic solute is the number of ions that are present in a solution. The equation for the ionization of sodium chloride follows:

NaCl(aq.)\rightarrow Na^{+}(aq.)+Cl^-(aq.)

The total number of ions present in the solution are 2.

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (NaCl) = 7.57 g

M_{solute} = Molar mass of solute (NaCl) = 58.44 g/mol

W_{solvent} = Mass of solvent (liquid X) = 350.0 g

Putting values in above equation, we get:

\text{Molality of }NaCl=\frac{7.57\times 1000}{58.44\times 350.0}\\\\\text{Molality of }NaCl=0.370m

To calculate the depression in freezing point, we use the equation:

\Delta T=iK_fm

where,

i = Vant hoff factor = 2

K_f = molal freezing point depression constant = 6.90°C/m

m = molality of solution = 0.370 m

Putting values in above equation, we get:

\Delta T=2\times 6.90^oC/m.g\times 0.370m\\\\\Delta T=5.11^oC

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

\Delta T=\text{freezing point of water}-\text{freezing point of solution}

\Delta T = 5.11 °C

Freezing point of water = 0°C

Freezing point of solution = ?

Putting values in above equation, we get:

5.106^oC=0^oC-\text{Freezing point of solution}\\\\\text{Freezing point of solution}=-5.11^oC

Hence, the freezing point of solution is -5.11°C

7 0
4 years ago
Calculate the grams of ethane present in a sample containing 0.4271 moles if the molar mass of ethane is 30.067 g/mol.
adelina 88 [10]

The grams of ethane present in a sample containing 0.4271 mole is 12.84 g

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation

Mole = mass / molar mass

With the above formula, we can obtain the mass of ethane. Details below

<h3>How to determine the mass of ethane</h3>

The following data were obtained from the question:

  • Mole of ethane = 0.4271 mole
  • Molar mass of ethane = 30.067 g/mol
  • Mass of ethane =?

The mass of ethane present in the sample can be obtained as follow:

Mole = mass / molar mass

Cross multiply

Mass = mole × molar mass

Mass of ethane = 0.4271 × 30.067

Mass of ethane = 12.84 g

Learn more about mole:

brainly.com/question/13314627

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5 0
2 years ago
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