A. SO2Cl2(g) --> SO2(g) + Cl2(g)
<span>1 mole of SOCl2 becomes 1 mole SO2 and 1 mole Cl2 </span>
<span>1 mole --> 2 moles </span>
<span>entropy increases </span>
Answer:
142240
Explanation:
We are told in the question:
Height of Gateway Arch in St. Louis, MO = 630ft
We are asked, how many U.S. dimes would be in a stack of the same
height when 1 dime is 1.35 mm thick.
Step 1
Convert height in ft to mm
1 ft = 304.8 mm
630ft =
Cross Multiply
630ft × 304.8mm/1ft
= 192024 mm.
Step 2
To find how many US dimes would be in a stack of the same height
= Total thickness/ Thickness of 1 US dime
= 192024 mm/1.35mm
= 142240
Therefore, the number of dimes that would be in a stack of the same
height is 142240
Is the something missing from the question
Answer:
The Equilibrium constant K is far greater than 1; K>>1
Explanation:
The equilibrium constant, K, for any given reaction at equilibrium, is defined as the ratio of the concentration of the products raised to their stoichiometric coefficients divided by the concentration of reactants raised to their stoichiometric coefficients.
It tells us more about how how bigger or smaller the concentration of products is to that of the reactants when a reaction attains equilibrium. From the given data, as the color of the reactant mixture (Br2 is reddish-brown, and H2 is colourless) fades, more of the colorless product (HBr is colorless) is being formed as the reaction approaches equilibrium. This indicates yhat the concentration of products becomes relatively higher than that of the reactants as the reaction progresses towards equilibrium, the equilibrium constant K, must be greater than 1 therefore.
The term isoelectronic atoms means that if the given atoms are neutral, they would have the same number of electrons, which is relative to their sizes. Ions with positive charges are called cations, losing electrons. On the other hand, ions with negative charges are called anions, gaining electrons. The more electrons that the atoms have, the bigger it is in size. Hence, the arrangement of the radii of the atoms would have to be,
e²⁺, d⁺, c , b⁻, a⁻
The arrangement is from smallest to largest.