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3 years ago

How are glucose and galactose epimers?

Chemistry

2 answers:

lisov135 [29]3 years ago

5 0

Answer:

<em>hehe I needed some brianliest plz OK </em>

Explanation:

<em>Glucose and galactose are monosaccharides that differ from one another only at position C-4. Thus, they are epimers that have an identical configuration in all the positions except in position C-4. ... Glucose and galactose are epimers that do not differ in position C-5 but differ in position C-4.</em>

Colt1911 [192]3 years ago

3 0

Glucose and mannose are epimers that differ at the C-2 carbon, while glucose and galactose are epimers that differ at the C-4 carbon, as shown below. When a molecule such as glucose converts to a cyclic form, it generates a new chiral center at C-1.

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Rina8888 [55]

<span>It is because air is a poor conductor of heat. Good luck ;)</span>

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3 years ago

<img src="https://tex.z-dn.net/?f=H_2PO_4%5E-%28aq%29%20%5Crightarrow%20H%5E%2B%28aq%29%20%2B%20HPO_4%5E%7B2-%7D%28aq%29" id="Te

klasskru [66]

Answer:

The pH of the buffer solution = 8.05

Explanation:

Using the Henderson - Hasselbalch equation;

pH = pKa₂ + log ( [HPO₄²-]/[H₂PO4⁻]

where pKa₂ = -log (Ka₂) = -log ( 6.1 * 10⁻⁸) = 7.21

Concentration of OH⁻ added = 0.069 M (i.e. 0.069 mol/L)

[H₂PO4⁻] after addition of OH⁻ = 0.165 - 0.069 = 0.096 M

[HPO₄²-] after addition of OH⁻ = 0.594 + 0.069 = 0.663 M

Therefore,

pH = 7.21 + log (0.663 / 0.096)

pH = 7.21 + 0.84

pH = 8.05

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3 years ago

An experiment applies heat to a substance and produces a gas that is a new and different substance. Choose the true statement.

sukhopar [10]

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3 years ago

0.500 mile of potassium oxide is dissolved in enough water to make 2.00 L of solution. Calculate the molarity of this solution (

SCORPION-xisa [38]

The correct question is as follows: 0.500 moles of potassium oxide is dissolved in enough water to make 2.00 L of solution. Calculate the molarity of this solution (plz help!)

Answer: The molarity of this solution is 0.25 M.

Explanation:

Molarity is the number of moles of a substance divided by volume in liter.

As it is given that there are 0.5 moles of potassium oxide in 2.00 L of water so, the molarity of this solution is calculated as follows.

$Molarity = \frac{moles}{volume(in L)}\\= \frac{0.5 moles}{2.00 L}\\= 0.25 M$

Thus, we can conclude that molarity of this solution is 0.25 M.

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2 years ago

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Answer:

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Explanation:

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