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Slav-nsk [51]
3 years ago
15

Its 8:05 i read for 30 mins what time did i start ?​

Mathematics
2 answers:
IRISSAK [1]3 years ago
5 0

Answer:

7:35 is when you started

Step-by-step explanation:

kati45 [8]3 years ago
5 0
I agree ^ with this dude
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It’s pre algebra finding y axis help with slope
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(0,-2) , good luck >>>>>>>>>
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2 years ago
Write the equation of a line with a slope of 3 and a y-intercept of 4
katrin [286]

Answer:

y = 3x + 4

Step-by-step explanation:

7 0
3 years ago
A rectangle or piece of paper has a width is 3 inches less than its link it is cut in half along a diagonal to create two congru
kolezko [41]

The length and width of the rectangle is 11 in and 8 in respectively.

Step-by-step explanation:

Given,

The width of a rectangle is 3 in less than the length.

The area of each congruent right angle triangle = 44 in²

To find the length and width of the rectangle.

Formula

The area of a triangle with b base and h as height = \frac{1}{2}bh

Now,

Let, the width = x and the length = x+3.

Here, for the triangle, width will be its base and length will be its height.

According to the problem,

\frac{1}{2}×(x+3)×x = 44

or, x^{2} +3x = 88

or,x^{2} +3x-88 = 0

or, x^{2}+(11-8)x-88 = 0

or, x^{2}+11x-8x-88 =0

or, x(x+11)-8(x+11) = 0

or, (x+11)(x-8) = 0

So, x = 8 ( x≠-11, the length or width could no be negative)

Hence,

Width = 8 in and length = 8+3 = 11 in

3 0
3 years ago
Find the missing side lengths (Use sqrt in place of a square root symbol)
Kitty [74]

Step-by-step explanation:

Because this is a right triangle and it is given that one angle is 45 than also the ather angle is 45 so this triangle has 2 equal sides.So also the ather side is 6 .

Hypotenuse can be found by pythagorean theorem

6^2+6^2=x^2

36+36=x^2

x=√72

8 0
3 years ago
Given:
Natali [406]

Answer:

\overline{PM}\cong\overline{ON}:, Segment subtended by the same angle on two adjacent parallel lines are congruent

Step-by-step explanation:

Statement,                                              Reason

MNOP is a parallelogram:,                     Given

\overline{PM}\left |  \right |\overline{ON}:,                                               Opposite sides of a parallelogram

∠PMO ≅ ∠MON:,                                    Alternate Int. ∠s Thm.

\overline{MN}\left |  \right |\overline{PO}:,                                               Opposite sides of a parallelogram

∠POM ≅ ∠NMO:,                                    Alternate Int. ∠s Thm.

OM ≅ OM:,                                               Reflexive property

\overline{PM}\cong\overline{ON}:,                                               Segment subtended by the same                                                                                                                              angle and on two adjacent parallel lines are congruent

4 0
3 years ago
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