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Pavlova-9 [17]
3 years ago
12

Question 1 2XY3 + 3XY3 5X2Y6 True or False

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
8 0
I would say is true because ur adding
Law Incorporation [45]3 years ago
5 0
U believe it’s F....
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A recent survey indicated that the average amount spent for breakfast by business managers was $9.33 with a standard deviation o
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Answer:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{9.41-9.33}{\frac{0.24}{\sqrt{81}}}=3    

Step-by-step explanation:

Information given

\bar X=9.41 represent the sample mean

s=0.24 represent the sample standard deviation

n=81 sample size  

\mu_o =9.33 represent the value to verify

\alpha=0.05 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is higher than 9.33, the system of hypothesis would be:  

Null hypothesis:\mu \leq 9.33  

Alternative hypothesis:\mu > 9.33  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{9.41-9.33}{\frac{0.24}{\sqrt{81}}}=3    

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Explanation:

Hope this helps!

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Step-by-step explanation:

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Step-by-step explanation:

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