Answer:
<em><u>D</u></em>
Step-by-step explanation:
When the denominator is equal to 0, the function doesn't exist. So factor the bottom, luckily its already partially factored.
(x^2 + 8x + 12) = (x+2)(x+6)
So now the denominator is (x+2)(x+6)(x-3)
The function doesn't exist when x = -2, -6, 3
Now we know there are 3 total discontinuities.
<u>A and B can be eliminated</u>
Since there is an (x+2) on the top and the bottom, they don't affect the shape of the function, but only causes a removable discontinuity when x = -2.
However, (x+6) and (x-3) are only on the bottom, so they DO change the shape, so they are non-removable
The answer therefore is 1 removable and 2 non-removable; D
The value of x in the following diagram in which the length of Q to line EF is 3x+1 and the length of Q from the line HG is x+8, is 3.5 units.
<h3>What is the property of perpendicular on chord in circle?</h3>
The line which is drawn from the center of the circle perpendicular to the chord in the circle bisect the chord into two equal shape.
In the given, diagram the length of Q to line EF is 3x+1 and the length of Q from the line HG is x+8.
These both the lines are equal in length as both are drawn from the center of the circle and has a perpendicular bisector for the 15 units length chord in the circle. Thus,
Thus, the value of x in the following diagram in which the length of Q to line EF is 3x+1 and the length of Q from the line HG is x+8, is 3.5 units.
Learn more about perpendicular on chord in circle here;
brainly.com/question/12628350
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Answer:
Rewritten in slope-intercept form,
y = mx + b
The answer is
y = 3/5x + 2.
<span>A circle is 360° all the way around; therefore, if you divide an arc’s degree measure by 360°, you find the fraction of the circle’s circumference that the arc makes up. Then, if you multiply the length all the way around the circle (the circle’s circumference) by that fraction, you get the length along the arc.</span>
