I think the answer is -2.7f-25 because if you subtract -2.3 F + .4 F then you do -16-9 I could be wrong warning
Slope = (y2 - y1) / (x2 - x1)
(5,3)...x1 = 5 and y1 = 3
(8,-2)..x2 = 8 and y2 = -2
now we sub
slope = (-2 - 3) / (8 - 5) = -5 / 3
y = mx + b
slope(m) = -5/3
use either of ur points..(5,3)...x = 5 and y = 3
now we sub and find b, the y int
3 = -5/3(5) + b
3 = -25/3 + b
3 + 25/3 = b
9/3 + 25/3 = b
34/3 = b
ur equation is y = -5/3x + 34/3...but we need it in standard form
y = -5/3x + 34/3
5/3x + y = 34/3
5x + 3y = 34 <=== standard form
The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
Step-by-step explanation:
The coefficent of the x variable is b.
The formula for the period is
Here, b is 6 so we have
So the period is pi/3, or 60 degrees
No, because if you add it up all together her recipe does not call for 20 cups.
