All categories

3 years ago

2 Doctors is _______________% of 25 Doctors what is it.

Mathematics

2 answers:

melisa1 [442]3 years ago

8 0

Answer:

Step-by-step explanation:

if you divide 2 by 25, you would get 0.08, which is equal to 8%

Valentin [98]3 years ago

6 0

Answer:

Step-by-step explanation:

You might be interested in

Here someone help me is this correct or no someone reported me saying it was wrong

Neko [114]

$-2^{4} = 16$

You're right.

8 0

3 years ago

Read 2 more answers

What are all the solutions of x2 + 3x - 4 = 0? 3 ооооооо DONE

Allisa [31]

Answer:

x = -4, x = 1

Step-by-step explanation:

Now I do not know why you said done, but just saying, if you are done with a question, you should delete it. Now I am just going to assume you knew this and move on with the solution of the problem.

When you factor this equation, you will get (x+4)(x-1).

You can then solve for x using zero product property. The first root is -4 and the second root is 1.

4 0

3 years ago

Venn diagrams: unions, intersections, and complements Attached is the photo references

ohaa [14]

Answer:

4, 8

Step-by-step explanation:

D iswholly part of B. so B intersect D is D

3 0

2 years ago

Read 2 more answers

A square has a perimeter of 52cm , what is the area ?

UNO [17]

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

❖ The area is 169 square cm.

Find the value of each side (a square has 4 sides so divide by 4 ):

52/4 = 13

To find the area of a square, you only need 2 sides so multiply 2 sides:

13 x 13 = 139

Area = 139 square cm

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

4 0

3 years ago

At what point on the paraboloid y = x2 + z2 is the tangent plane parallel to the plane 3x + 2y + 7z = 2? (if an answer does not

Nikitich [7]

If $f(x, y, z) = c$ represent a family of surfaces for different values of the constant $c$ . The gradient of the function $f$ defined as $\nabla f$ is a vector normal to the surface $f(x, y, z) = c$ .

Given the paraboloid

$y = x^2 + z^2$ .

We can rewrite it as a scalar value function f as follows:

$f(x,y,z)=x^2-y+z^2=0$

The normal to the paraboloid at any point is given by:

$\nabla f= i\frac{\partial}{\partial x}(x^2-y+z^2) - j\frac{\partial}{\partial y}(x^2-y+z^2) + k\frac{\partial}{\partial z}(x^2-y+z^2) \\ \\ =2xi-j+2zk$

Also, the normal to the given plane $3x + 2y + 7z = 2$ is given by:

$3i+2j+7k$

Equating the two normal vectors, we have:

$2x=3\Rightarrow x= \frac{3}{2} \\ \\ -1=2 \\ \\ 2z=7\Rightarrow z= \frac{7}{2}$

Since, -1 = 2 is not possible, therefore there exist no such point on the paraboloid $y = x^2 + z^2$ such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2.

4 0

3 years ago