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Stells [14]
4 years ago
7

What theorem can be used to prove that the two triangles are congruent?

Mathematics
2 answers:
maw [93]4 years ago
7 0

AAS(angle-angle-side), SSS(side-side-side), SAS(side-angle-side), ASA(angle-side-angle), and HL(hypotenuse-length)

stellarik [79]4 years ago
3 0

Answer:

To prove the congruence between two triangles there are several postulates, that can be applied depending on the congruent parts of the triangles.

The postulates are:

  • SAS (Side-Angle-Side): This postulate states that if two triangles have two corresponding sides congruent and one corresponding angle congruent, we can conclude that those triangles are completely congruent.
  • ASA (Angle-Side-Angle): This postulate states that if two triangles have two corresponding angles congruent and one corresponding side congruent, then those triangles are congruent.
  • SSS (Side-Side-Side): This postulate states that if two triangles have all three corresponding sides congruent, then triangles are congruent.
  • AAS (Angle-Angle-Side): If two pairs of corresponding angles are congruent and one pair of corresponding sides is congruent, then both triangle are congruent each other.
  • HL (Hypothenuse-Leg): this postulate is applied when we have right angles. It states that two right triangles are congruent if they have one pair of corresponding leg congruent, and the hypothenuses are also congruent. We could conclude that those right triangles are congruent.

From these postulate, we can demonstrate the congruence between two triangles. Then, from that congruence, we deduct the congruence between each corresponding parts of those triangles. For example, if we demonstrate the congruence by AAS, we deduct that the third angle is also congruent, and the other two sides are also congruent.

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B.

Step-by-step explanation:

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Arte-miy333 [17]

Answer:

Part A) The graph in the attached figure (see the explanation)

Part B) The ordered pair is not included in the solution area for the system (see the explanation)

Step-by-step explanation:

Part A) we have

y ----> inequality A

The solution of the inequality A  is the shaded area below the dashed line y=4x-8

The slope of the dashed line is positive

The y-intercept of the dashed line is (0,-8)

The x-intercept of the dashed line is (2,0)

y\geq -\frac{5}{2}x+5 ----> inequality B

The solution of the inequality B is the shaded area above the solid line y=-\frac{5}{2}x+5

The slope of the solid line is negative

The y-intercept of the solid line is (0,5)

The x-intercept of the solid line is (2,0)              

The solution of the system of inequalities is the shaded area between the dashed line and the solid line

see the attached figure

Part B) is the point (5, -8) Included in the solution area for the system?

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities

Substitute the value of x=5, y=-8 in each inequality and then analyze the results

<em>Inequality A</em>

-8

-8 ----> is true

so

the ordered pair satisfy inequality A

<em>Inequality B</em>

-8\geq -\frac{5}{2}(5)+5

-8\geq -7.5 ---> is not true

so

the ordered pair not satisfy the inequality B

therefore

The ordered pair is not included in the solution area for the system

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2X+2+4=8
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Simply (cotθ-cscθ)^2
DIA [1.3K]

Answer:

[(cosθ-1)^2]/(sinθ)^2

Step-by-step explanation:

(cotθ-cscθ)^2

(cotθ)^2-<em>2cscθcotθ</em>+<u>(cscθ)^2</u>

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((cosθ)^2-2cosθ+1)/(sinθ)^2

Factor the top

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