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3 years ago

PLEASE HELP (PRE ALGEBRA)

Mathematics

1 answer:

densk [106]3 years ago

3 0

Answer: r = 4

Step-by-step explanation:

V = pi * r^2 * h

144 * pi = pi * r^2 * 9

Divide by pi

144 = r^2 * 9

Divide by 9

16 = r^2

Take square root of both sides

rad(16) = rad(r^2)

4 = r

r = 4

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I give you a tricky one Express 108 ×125as a product of prime factors in exponential form

lana [24]

Answer:

$108 \times 125=2^2 \times 3^3 \times 5^3$

Step-by-step explanation:

To express the given product (108 X 125) as a product of prime factors

Step 1: Express each of the numbers as a product of its prime factors.

$108=2^2 \times 3^3\\125=5^3$

Step 2: Write the product together, and combine any like terms if any

Therefore,

$108 \times 125=2^2 \times 3^3 \times 5^3$

8 0

3 years ago

a daily newspaper has 10225 subscribers when it began publication. six years old later it has 8200 subscribers what is the avera

seraphim [82]

Answer:

The rate of change in number of subscriber for the six years is 3.62%

Step-by-step explanation:

Given as :

The initial subscriber of newspaper = p = 10225

The subscriber of newspaper after 6 years of publish = P = 8200

The time period = t = 6 years

Let The average yearly rate of change = r%

<u>Now, According to question</u>

The subscriber of newspaper after n years = initial subscriber × $(1-\dfrac{\textrm rate}{100})^{\textrm time}$

Or, P = p × $(1-\dfrac{\textrm r}{100})^{\textrm t}$

Or, 8200 = 10225 × $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Or, $\dfrac{8200}{10225}$ = $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Or, 0.80195 = $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

<u>Taking power $\dfrac{1}{6}$ both side</u>

So, $(0.80195 )^{\frac{1}{6}}$ = $((1 - \frac{r}{100} )^{6})^{\frac{1}{6}}$

Or, 0.9638 = 1 - $\dfrac{r}{100}$

Or, $\dfrac{r}{100}$ = 1 - 0.9638

Or, $\dfrac{r}{100}$ = 0.0362

Or, r = 0.0362 × 100

i.e r = 3.62

So, The rate of change in subscriber = 3.62%

Hence, The rate of change in number of subscriber for the six years is 3.62% . Answer

4 0

3 years ago

HELP ASAP TRYING TO PASS MATHHHH If a rectangle lying completely in quadrant I is rotated counter-clockwise 270

koban [17]

Hear is the link for the answer
Https//gh6js

8 0

3 years ago

Read 2 more answers

PLSSSS HELLLPPPPPPP How much would it cost to buy 3.4 pounds of Bartlett pears and 2.1 pounds of Concorde pears? Concorde pears

kirill [66]

Answer:

$13.10

Step-by-step explanation:

Concard $3.00 2.1 $6.30

Osband $3.00

Green Anjou $4.00

Bartlett $2.00 3.4 $6.80

Red Anjou $5.00

TOTAL = $13.10

5 0

3 years ago

the coordinates of a line segment are (1,6) and (11, -4). what is the length of the line segment? round your answer to the neare

ddd [48]

The length of the line segment AB where $A(x_A;\ y_A)$ and $B(x_B;\ y_B)$

$|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}$

We have: $A(1;\ 6);\ B(11;-4)$

subtitute

$|AB|=\sqrt{(1-11)^2+(6-(-4))^2}=\sqrt{(-10)^2+10^2}=\sqrt{100+100}\\\\=\sqrt{100\cdot2}=\sqrt{100}\cdot\sqrt2=10\sqrt2\approx14.1$

Answer: b. 14.1

3 0

3 years ago