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cluponka [151]
3 years ago
10

What is the area of the paper used to wrap a can of soup if the can is 11 cm tall and has a diameter of 7.5 cm. Show all formula

s and work.
Mathematics
1 answer:
Dimas [21]3 years ago
6 0

Notice that a can is a cylinder, which is basically two circles and one rectangle. Now, the question wants area of this rectangle.

You know the width of the rectangle (or the paper), which is 11cm. How do you find the length then?

Notice that the length of the rectangle is also the circumference of the circles. From here, use C = πd where C is circumference and d is diameter. The d is given, which is 7.5 cm. Depending on the question, π can be 3.14, 22/7 or the actual pi.

multiply π and 7.5cm and you get the circumference. Multiply this to 11cm and you get area of the rectangle.

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A pre-algebra book is 8 1 half inches by 9 1 fourth inches. Determine the perimeter of the textbook.
Arisa [49]

Answer:

Rectangular book--

two 8 1/2 sides

two 9 1/4 sides

8 1/2*2=17

9 1/4*2=18 1/2

17+18 1/2= 35 1/2

The perimeter of the textbook is 35 1/2 inches or 35.5 inches.

-this is not mine btw creds to sunflowerem :))

8 0
3 years ago
5b - 5 - 12b - 7<br> I need steps please and thank you
Misha Larkins [42]

Answer:

7b-12

Step-by-step explanation:

12b-5b-7-5

7b-12

8 0
3 years ago
Help me<br> Is not an exam is a activity
Talja [164]

Answer:

B. y= -2x +2

Step-by-step explanation:

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7 0
3 years ago
Find n. 8/12 = n/48. n = ?
Novosadov [1.4K]

Answer:

n = 32

Step-by-step explanation:

<u><em>Given:</em></u>

<u><em></em></u>\frac{8}{12}=\frac{n}{48}

<u><em>Solve:</em></u>

<em />\mathrm{Cross\; Multiply:}

<em />\frac{8}{12}=\frac{n}{48}

\mathrm{48\times8=384}

\mathrm{384\div12=32}

\mathrm{Hence,n=32}

~\mathrm{[Kavinsky]}

7 0
2 years ago
Read 2 more answers
How do you find the area of the field in <br> terms of x
Alex_Xolod [135]

Hello from MrBillDoesMath!


Answer:  104x^2 + 166x + 66

Discussion:

The area of a rectangle is given by "length" * "width". For us the formula becomes

 (13x + 11) * (8x+6)


or

13x (8x +6) + 11 * (8x + 6)  =


(13x * 8x + 13x* 6) + ( 11*8x + 11*6) =

(104x^2 + 78x ) + (88x + 66) =

104x^2 + (78x + 88x) + 66 =


104x^2 + 166x + 66


Thank you,

MrB

4 0
3 years ago
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