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3 years ago

Which amount of 1 inch square pieces of chocolate would you

Mathematics

2 answers:

kherson [118]3 years ago

7 0

Step-by-step explanation:

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nexus9112 [7]3 years ago

5 0

a. Chocolate need to cover a rectangle with a length of 9 in. and a perimeter of 22 inches is 18 pieces of 1 inch square piece chocolates

b.Chocolate need to cover a rectangle with a length of 5 in. and a perimeter of 20 inches is 20 pieces of 1 inch square piece chocolates

Step-by-step explanation

a. To cover a rectangle with a length of 9 in. and a perimeter of 22 in.

perimeter = 2(length+breadth)

Breadth = 22 -9×2 = 22-18 = 4 ÷ 2 = 2 inches

Area of rectangle = 9 × 2 = 18 inches

18 pieces of 1 inch square piece Chocolate is needed to cover the rectangle

b. To cover a rectangle with a length of 5 in. and a perimeter of 20 in.

perimeter = 2(length+breadth)

Breadth = 20 - 5 ×2 = 10 = 10 ÷ 2 = 5 inches

Area of rectangle = 5 × 5 = 20 inches

20 pieces of 1 inch square piece Chocolate is needed to cover the rectangle

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Am i correct? calculus

Advocard [28]

Check the picture below.

now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer. That matters because the derivative of a constant is zero.

now, those are the values when the rocket is 30 feet up above.

$\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y
\\\\\\
\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}
\\\\\\
\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\
-------------------------------\\\\
$

$\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\
-------------------------------\\\\
\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}
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\cfrac{d\theta }{dt}=\cfrac{11}{75}$

8 0

3 years ago

In the morning, the temperature was 15∘F. During the day, the temperature fell 37 degrees. Which expression shows how to find th

tino4ka555 [31]

Answer:

- 22°F

Step-by-step explanation:

Given that :

Morning temperature = 15°F

Change in temperature = fall by 37 degree

The temperature of the end of the day:

Morning temperature + (change in temperature)

Fall by 37° = decrease in temperature by 37° = - 37°

15°F + (-37°F)

15°F - 37°F

= - 22°F

6 0

2 years ago

A triangle has side lengths of (10x + 7y) centimeters, (3x + 3z) centimeters, and (8z +10y) centimeters. Which expression repres

Kay [80]

Answer:

(D) 13x + 17y + 11z

is right answer

8 0

2 years ago

What type of association would you expect to see between the amount of fog in the sky and the distance that a pilot can see? A)

Blizzard [7]

We can make a conclusion that the more fog there is, the less distance the pilot can see. this means that there is a negative association because if this were graphed, the slop would be negative, as the x-axis (amount of fog) increases and the y-axis (distance pilot can see) decreases.

7 0

3 years ago

4×+12=36 what number goes in the x?

Nataliya [291]

You can work this out by rearranging the equation and isolating the x.

4x + 12 = 36

4x = 36 - 12 (I moved the +12 to the other side, which means it becomes -12)

4x = 24 (36 - 12 = 24)

x = 24 / 4 (You need to isolate the x, and because it was being multiplied by 4, I divided both sides by 4 to leave me with just x)

x = 6 (24 divided by 4 is 6).

8 0

3 years ago