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3 years ago

HELP PLEASEEEEEEEEEEEEE

Mathematics

2 answers:

stepan [7]3 years ago

7 0

Answer:

1)68

2)46

Step-by-step explanation:

Dima020 [189]3 years ago

3 0

Answer:

1. 112

2. 46

Step-by-step explanation:

When two parallel lines are intersected by a transversal, the alternate interior angles are supplementary. Meaning that their angle measures add up to 180 degrees. Set up an equation and solve for the unknown angle using inverse operations.

$68 + ? = 180\\-68\\\\? = 112$

When two parallel lines are intersected by a transversal, the corresponding angles are congruent, in other words, they have the same angle measure.

$? = 46$

You might be interested in

What is equivalent to 22c+33d

Fofino [41]

Answer:

11 (2c+3d)

Step-by-step explanation:

3 0

4 years ago

The probability that…. The student is not female or received a degree outside of the field

a_sh-v [17]

Answer: 0.8953 (approximate)

The more accurate value is 0.89528093209023; however, it's not entirely exact either. Round that however you need.

===========================================================

Explanation:

There are 774,517 males and 1,400,843 people who got their degree outside of the field. Add those values

774,517+1,400,843 = 2,175,360

This unfortunately double counts the number of males who got their degree outside of the field (576,228) so we need to subtract that count off

2,175,360 - 576,228 = 1,599,132

------------------------

There are 1,599,132 people who are either

A) male
B) got their degree outside the field, or,
C) both male and got their degree outside the field

This is out of 1,786,179 people total.

We'll divide these two values to get the final answer

(1,599,132)/(1,786,179) = 0.89528093209023

It's not clear how your teacher wants you to round this. If you round it to say 4 decimal places, then you'd get approximately 0.8953

The chances of the student not being a female or receiving their degree outside the field is roughly 89.53%

8 0

2 years ago

What is the sum of StartRoot negative 2 EndRoot and StartRoot negative 18 EndRoot? 4 StartRoot 2 EndRoot 4 StartRoot 2 EndRoot i

Sveta_85 [38]

Adding $\sqrt{-2}\,\,and\,\,\sqrt{-18}$ we get $4\sqrt{2i}$

Option C 4 StartRoot 2 EndRoot i is correct.

Step-by-step explanation:

We need to find the sum of: $\sqrt{-2}\,\,and\,\,\sqrt{-18}$

Finding sum:

$\sqrt{-2}+\sqrt{-18}$

$\sqrt{-2}$ can be written as $\sqrt{2}i$

$\sqrt{-18}$ can be written as $\sqrt{18}i$

We know 18 = 2x3x3 = 2x3^2 so,

$\sqrt{2i}+\sqrt{2\times 3^2}i$

$\sqrt{2i}+3\sqrt{2}i$

Adding like terms:

$4\sqrt{2i}$

So, adding $\sqrt{-2}\,\,and\,\,\sqrt{-18}$ we get $4\sqrt{2i}$

Option C 4 StartRoot 2 EndRoot i is correct.

Keywords: Square root expressions

Learn more about Square root expressions at:

#learnwithBrainly

6 0

3 years ago

Read 2 more answers

Community college students conduct a survey at their college. They ask "Do you plan to transfer to a university to pursue a bacc

Tamiku [17]

Answer:

$0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697$

$0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903$

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case the conditions we have the conditions to assume a normal distribution for the population proportion since:

np=100*0.8=80 >10 , n(1-p) = 10*(1-0.8) =20 >10

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by: