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3 years ago

Diberi fungsi f:x = 2x + 5 dan g:x=X^2-3,cari f^-1g(-3)

Mathematics

1 answer:

zloy xaker [14]3 years ago

6 0

Hmm I think the answer is 452

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Reduce to simplest form.<br> -7/12 + 3/8<br> (They are fractions)

denpristay [2]

Answer:

-5/24

Step-by-step explanation:

You first change -7/12 to -14/24, and 3/8 to 9/24 so they have the same denominator. You then do -14/24 + 9/24. That will be the same as the opposite of the answer to 14/24 - 9/24.

14/24 - 9/24 = 5/24

-5/24

4 0

3 years ago

Help please with this asap

nikdorinn [45]

Y = 3000x + 28000
y = 2800x + 30000

3000x + 28000 = 2800x + 30000
200x = 2000
x = 10

The salaries will be the same after 10 years.

5 0

3 years ago

Read 2 more answers

An assembly line inspector inspected 340 machine parts. 323 of the parts passed inspection. What percent of the machine parts di

tester [92]

Answer:

5% did not pass inspection

Step-by-step explanation:

Given

$Inspected= 340$

$Passed = 323$

Required

Determine the percentage of parts that didn't pass inspection.

First, we need to calculate the number of those that didn't pass inspection.

$Failed = Inspected - Passed$

$Failed = 340 - 323$

$Failed = 17$

Next, we calculate the percentage as follows:

$\% = \frac{Failed}{Inspected} * 100\%$

The above formula is derived by dividing the number of parts that didn't pass inspection by the total machine inspected, then multiplied by 100%

So:

$\% = \frac{17}{340} * 100\%$

$\% = \frac{17 * 100\%}{340}$

$\% = \frac{1700\%}{340}$

$\% = 5\%$

<em>5% did not pass inspection</em>

6 0

3 years ago

Priscilla invests $10,000 in an account that compounds interest continuously and earns 11%. How long will it take for her money

Shkiper50 [21]

Answer:

Step-by-step explanation:

When the interest compounds continuously, our formula is

$A(t)=Pe^{rt}$

If we start with 10000 and are looking for how long, t, it takes to double, we are looking for how long it will take for our account to have 2 times 10000. That's 20000. Therefore, our equation is

$20000=10000e^{.11t}$