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NikAS [45]
3 years ago
5

Which is greater 3/4 or 10/12

Mathematics
2 answers:
Lelu [443]3 years ago
8 0
10/12 is greater than 3/4.

10/12 = 5/6 > 10/12
Korolek [52]3 years ago
3 0
3/4 is greater because it has less and only one away from the four
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The length of a rectangle is 1 more yd than twice the width, and the area of the rectangle is 66 yd squared. Find the dimensions
Salsk061 [2.6K]

Width = 5.5yd  

Length = 12yd

<u>Explanation:</u>

Area of rectangle =  66yd^{2}

Let width of the rectangle = b ,  

So, length = 2b+1  

Area of rectangle = (length X width) - eqn 1

Putting the value of length and width in above equation 1,

66yd^{2} = (2b+1) X b\\66yd^{2} = 2b^{2} + b\\2b^{2} +b-66 = 0\\

On solving the equation we get,

b = 5.5yd

So, width (b) = 5.5yd

and length = 2(5.5) + 1

l = 12yd

Hence,  

Width = 5.5yd  

Length = 12yd

6 0
3 years ago
What is the answer to the question
Savatey [412]

i really don't understand this question

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7 0
2 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
A triangle with side length of 4 inches, 7 inches and 10 inches is
nexus9112 [7]

Answer:

scalene

Step-by-step explanation:

also an acute triangle is something to do with angles so as long as no angles are provided, scalene is the best option

4 0
3 years ago
Their win percentage was 40, then how many matches did they play in all!
Neko [114]

Answer:

14400

Step-by-step explanation:

X - X × 75%=3600

X - X × \frac{75}{100} = 3600

X - \frac{3X}{4} = 3600

\frac{4X-3X}{4} = 3600

\frac{X}{4} = 3600

X = 3600 × 4

X = 14400

3 0
2 years ago
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