Answer:
The minimum score required for admission is 21.9.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
A university plans to admit students whose scores are in the top 40%. What is the minimum score required for admission?
Top 40%, so at least 100-40 = 60th percentile. The 60th percentile is the value of X when Z has a pvalue of 0.6. So it is X when Z = 0.255. So
The minimum score required for admission is 21.9.
The answer must be A or B. Since the person is trying to pay for AS MUCH people as possible. So, therefore the answer is A.
Answer:
The answer is 18 percent, or 9/50.
Step-by-step explanation:
We first convert the chance of rain on Monday into a fraction.
60%=60/100=3/5.
We then convert the chance of rain on Tuesday into a fraction.
30%=30/100=3/10.
Because the two events are independent(i.e. If it rains on Tuesday doesn't depend on if it rains on Monday) we multiply them together to get the probability they both happen. That chance is:
3/5 * 3/10=(3*3)/(5*10)=9/50(fraction form)=18/100=18%(percent form)
50 People played an instrument. Every 10 people is represented as a 1 in the fraction. 5=50
Answer:
degree = 120°
A =67 cm²
d=?
note : diameter= 2×radius
area of a circle = πr²
67=22/7 ×r²
67×7=22r²
469=22r²
r²=469/22
r²=21.32
r=4.62
diameter=2 × radius
d= 2× 4.62
d=9.24
d=9
I hope it helps :)