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Nonamiya [84]
3 years ago
14

true or false. for a continuous function, of f(2) is negative and f(3) is positive, then there must be a zero between x=2 and x=

3​
Mathematics
1 answer:
Rashid [163]3 years ago
5 0

It's true. In general, if a function is continuous, and you have

f(x_1)=y_1,\quad f(x_2)=y_2

then f(x) spans all the possible values between y_1 and y_2 in the interval [x_1,x_2]

So, in particular, if you have

f(2) = y_2 < 0,\quad f(3) = y_3 > 0

you can conclude that in the interval [2,3], f(x) span all the values between y_2 and y_3, which include 0 because y_2 is negative and y_3 is negative.

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Step-by-step explanation:

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Vikentia [17]
<h2>Introduction</h2>

Hello! I hope you are having a nice day. My name is Galaxy and I will be helping you with this problem. We can solve this problem in 2 steps, respectively Theory and Solving.

I'll go ahead and start with the Theory.

<h2>Theory</h2>

Before we attempt to solve the problem mathematically, we must first figure out how we're going to solve this problem.  

We know that we have a line and a point, we can start by graphing the equation and point that we've received.

<h2 /><h2>Solving</h2>

Now that we have our points plotted and our equations graphed, we can start to see that something odd is happening, the given point is on the line itself.

We can check this by inputting the points into our equation:

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According to the basic rules of Euclidean Geometry, we know that parallel lines can never intersect each other and due to this there cannot be any solution to this problem.

Any other line using this point would intersect the given line, and due to this, this problem has no real solutions.

* The only line that can use these points and graph is the line provided, and that cannot work due to the lines intersecting at an infinite number of points.

Cheers,
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Step-by-step explanation:

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