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vaieri [72.5K]
3 years ago
5

Could the cross-section of a square be a triangle? Explain and draw a diagram to justify your answer.

Mathematics
1 answer:
den301095 [7]3 years ago
4 0

Yes

Step-by-step explanation:

As u can see in the diagram labelled 1-4 u can see 4 triangles ,

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Evaluate 4x2 +3 when x=5
Molodets [167]

Answer:

103

Step-by-step explanation:

We substitute x with 5:

4(5)^2+3

Solve the exponent first:

5^2 = 25

<em>Note: We are using order of operations (consecutively)</em>

  1. <em>Parentheses </em>
  2. <em>Exponents</em>
  3. <em>Multiplication</em>
  4. <em>Division</em>
  5. <em>Addition </em>
  6. <em>Subtraction</em>

Multiply:

25 * 4 = 100

Add:

100 + 3 = 103

Our answer is 103

<em />

7 0
3 years ago
Read 2 more answers
It’s not 3 but still need help with it
Leto [7]

Answer:

13

Step-by-step explanation:

5-(-8)=13

6 0
2 years ago
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1x -1y =100 x. what is the answer​
Bad White [126]

Answer:

y=-99x

Step-by-step explanation:

it's imposible to answer y in terms of a number, but it is possible to do it in terms of x.

x-y=100x

x=100x+y

-99x=y

y=-99x

8 0
3 years ago
I don't want a account I just want answers
IgorLugansk [536]
Answers for what ?:o
8 0
3 years ago
A simple random sample with n = 58 provided a sample mean of 24.5 and a sample standard deviation of 4.4. (Round your answers to
nasty-shy [4]

Answer: (23.53, 25.47)

Step-by-step explanation:

The confidence interval for population mean(when population standard deviation is unknown) is given by :-

\overline{x} \pm\ t^*\dfrac{s}{\sqrt{n}}

, where \overline{x} = sample mean

n = sample size.

s = sample standard deviation.

t* = Critical value.

Given : \overline{x}=24.5

s= 4.4

Confidence level = 90% =0.090

Significance level = \alpha=1-0.90=0.10

Sample size : n= 58

Degree of freedom : df= n-1= 57

Using t-distribution table , the critical value :

t_{\alpha/2,\ df}= t_{0.05,\ 57}=1.6720

Then, the confidence interval will be :-

24.5 \pm\ (1.6720)\dfrac{4.4}{\sqrt{58}}

24.5 \pm\ (1.6720)\dfrac{4.4}{7.61577310586}

24.5 \pm\ 0.965995165263\approx24.5\pm0.97\\\\=(24.5-0.97,\ 24.5+0.97)\\\\=(23.53,\ 25.47)

Hence, a 90% confidence interval for the population mean = (23.53, 25.47)

6 0
3 years ago
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