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denpristay [2]
2 years ago
11

3x2 = 6x - 3 O (1) O (-1,0) O (-1,1) O (-1)

Mathematics
1 answer:
natita [175]2 years ago
6 0

Answer:

I THINK ITS THE 3RD ONE

Step-by-step explanation:

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A cat jumps 5 feet in the span of 2 seconds. Find the unit rate, in feet per second, that the cat is moving at. Express any impr
mr_godi [17]

Divide total distance by total time:

5 feet / 2 seconds = 2 and 1/2 feet per second.

3 0
2 years ago
Which function has real zeros at x = 3 and x = 7
iren2701 [21]

Answer:

7

Step-by-step explanation:

okay

7 0
2 years ago
Mike grew 7 carrots but the rabbits ate 6 carrots how many carrots does mike have left
kaheart [24]

Answer:

Mike now has 1 carrot

Step-by-step explanation:

Mike has 7 carrots and the rabbit ate 6 so 7-6=1 :)

5 0
3 years ago
PLEASE HELP QUICK, I need to know the answer.
Marysya12 [62]

The equivalent expression is 7^{2}.

We have the following expression -

\frac{7^{-3} }{7^{-5} }

We have to find its equivalent value.

<h3>What is the equivalent expression of the following expression-</h3>

f(x, y) =\frac{A^{x} }{A^{y} }

In order to divide two exponents with same base, we use the 'Quotient property of exponents.

The equivalent expression can be written as -

f(x, y) = A^{x} A^{-y} = A^{x-y}

In the question given we have -

\frac{7^{-3} }{7^{-5} }

Using the property discussed above -

7^{-3}\;7^{5} = 7^{-3+5} = 7^{2}

Hence, the equivalent expression is 7^{2}.

To solve more questions on exponents, visit the link below -

brainly.com/question/17173276

#SPJ5

3 0
1 year ago
Read 2 more answers
100 POINTS HELP ASAP Linear Combination
notka56 [123]

Answer:

1)   x=\dfrac12

2)   n = -3 \ \ \textsf{and} \ \ m = -4

3)  see below

4)  A:  0 = 1

Step-by-step explanation:

<u>Question 1</u>

15-0.5(4x-2)+4x=17

\implies 15-2x+1+4x=17

\implies 2x+16=17

\implies 2x=1

\implies x=\dfrac12

<u>Question 2</u>

\textsf{rearrange} \ n=m+1 :

\implies -m=-n+1

\textsf{add equations} \ -m=-n+1 \ \textsf{and} \ m=2n+2:\\

\implies0=n+3

\implies n=-3

\textsf{substitute} \ \ n=-3 \ \ \textsf{into} \ \ m=n-1:

\implies m=-3-1

\implies m=-4

<u>Question 3</u>

subtract the second equation from the first

divide both sides by -4

substitute found value for y into first equation

solve for x

<u>Question 4</u>

3j=k

k=3j+1

\textsf{rearrange} \ 3j=k :

\implies -k=-3j

\textsf{add equations}\  -k=-3j \ \ \textsf{and}\ \ k=3j+1:

\implies 0=1

Solution = A

6 0
2 years ago
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