Start by setting up a factor tree for each number.
Factor in anyway that you'd like.
At the end, circle all prime numbers.
Remember, prime numbers are numbers
with only 2 factors, 1 and the number itself.
Now write these factors in least to greatest
multiplying them separate rows.
Circle factors they have in common.
Since 3 pairs of two's match up, multiply by 2 three times to get 8.
So the GCF is 8.
Answer:
0.918 is the probability that the sample average sediment density is at most 3.00
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 2.80
Standard Deviation, σ = 0.85
Sample size,n = 35
We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling:
P(sample average sediment density is at most 3.00)
Calculation the value from standard normal z table, we have,
0.918 is the probability that the sample average sediment density is at most 3.00