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abruzzese [7]
3 years ago
7

Find DF D 20 E 10 F DF =

Mathematics
2 answers:
vichka [17]3 years ago
8 0

Answer:

30

Step-by-step explanation:

it is right

erastovalidia [21]3 years ago
5 0
It’s 30!

bc DE is 20 and EF is 10, if DF is the entire segment, then you would add 20 & 10, to get 30.
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Two parallel lines are crossed by a transversal . What is the value of k?
bulgar [2K]

Answer:

The value of is equal to k=60\°

Step-by-step explanation:

we know that

(2k+11)\°=131\° -----> by alternate exterior angles

solve for k

2k=131\°-11\°

k=120\°/2=60\°

7 0
3 years ago
Read 2 more answers
Please show the working and answer. you can take a picture for the working.
baherus [9]

Answer:

(a) The area of the triangle is approximately 39.0223 cm²

(b) ∠SQR is approximately 55.582°

Step-by-step explanation:

(a) By sin rule, we have;

SQ/(sin(∠SPQ)) = PQ/(sin(∠PSQ)), which gives;

5.4/(sin(52°)) = 6.8/(sin(∠PSQ))

∴ (sin(∠PSQ)) = (6.8/5.4) × (sin(52°)) ≈ 0.9923

∠PSQ = sin⁻¹(0.9923) ≈ 82.88976°

Similarly, we have;

5.4/(sin(52°)) = SP/(sin(180 - 52 - 82.88976))

Where, 180 - 52 - 82.88976 = ∠PQS = 45.11024

SP = 5.4/(sin(52°))×(sin(180 - 52 - 82.88976)) ≈ 4.8549

Given that RS : SP = 2 : 1, we have;

RS = 2 × SP = 2 × 4.8549 ≈ 9.7098

We have by cosine rule, \overline {RQ}² =  \overline {SQ}² +  \overline {SR}² - 2 × \overline {SQ} × \overline {SR} × cos(∠QSR)

∠QSR and ∠PSQ are supplementary angles, therefore;

∠QSR = 180° - ∠PSQ = 180° - 82.88976° = 97.11024°

∠QSR = 97.11024°

Therefore;

\overline {RQ}² =  5.4² +  9.7098² - 2 ×  5.4×9.7098× cos(97.11024)

\overline {RQ}² ≈ 136.42

\overline {RQ} = √(136.42) ≈ 11.6799

The area of the triangle = 1/2 ×\overline {PQ} × \overline {PR} × sin(∠SPQ)

By substituting the values, we have;

1/2 ×\overline {PQ} × \overline {PR} × sin(∠SPQ)

1/2 × 6.8 × (4.8549 + 9.7098) × sin(52°) ≈ 39.0223 cm²

The area of the triangle ≈ 39.0223 cm²

(b) By sin rule, we have;

\overline {RS}/(sin(∠SQR)) = \overline {RQ}/(sin(∠QSR))

By substituting, we have;

9.7098/(sin(∠SQR)) = 11.6799/(sin(97.11024))

sin(∠SQR) = 9.7098/(11.6799/(sin(97.11024))) ≈ 0.82493

∠SQR = sin⁻¹(0.82493) ≈ 55.582°.

8 0
3 years ago
Please help my brain is mush i dont understand how this works nd i still have 11 assignments after this-
Mars2501 [29]

Answer:

See step by step

Step-by-step explanation:

1. First question, do they represent functions? The one o. the left is a function because if you do the vertical line test. It only passes through a point once so it is a function. while on the right if you do the vertical line test, it passes through a point twice so it not a function. For 2.. n other words, since the domain of this equation is all real numbers or negative infinity to positives infinity

let say x=1 and x=-1 and we use the equation

y =  {x}^{2}

when we plug both those in we get

y = 1

this means that we can have two different x-values to equal out to the same y value. This is the definition of a function. So the one on the right is a function.

However the one on the left is a relation. TO Prove it, the domain of that function is all real numbers equal to or greater than zero, so let use 4.

{y}^{2}  = 4

{y} = 2 \: or \:  - 2

Since there are 2 possible answer choices as the y value, this isn't a function. It a relation. It maps a group of ordered sets to one x value. Which is the opposite of the function. So the one of the left is a relation

3 0
3 years ago
70/9 as a mixed number
Makovka662 [10]
70/9
Divide 
9*7 = 63
70-63 = 7

7  7/9
7 0
3 years ago
Read 2 more answers
Select the correct answer from each drop-down menu.
kow [346]

Triangle ABC and triangle XYZ are similar based on angle-side-angle criterion.

Triangle ABC and triangle RQP are similar based on side-angle-side criterion.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Two triangles are said to be congruent if they have the same shape and their corresponding sides are congruent.

Triangle ABC and triangle XYZ are similar based on angle-side-angle criterion.

Triangle ABC and triangle RQP are similar based on side-angle-side criterion.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

5 0
1 year ago
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