Question

X+3y=-2 3x+4y=-6 USE SYSTEMS BY SUBSTITUTION. X= Y=

Answer 1

Answer:

X=-2

Y=0

Step-by-step explanation:

X+y=-2 = x=-2-y

3x+4y=-6

3(-2-y)+4y=-6

-6-3y+4y=-6

y=0

x+3(0)=-2

x=-2

Answer 2

Answer:

$\boxed {\boxed {\sf (-2,0)}}$

Step-by-step explanation:

To solve by substitution we must first isolate 1 variable in an equation.

Let's use the first equation.

$x+3y= -2$

Subtract 3y from both sides to isolate the variable x.

$x+3y-3y= -2 -3y$

$x= -2 -3y$

Now we can substitute the expression (-2-3y) in for x in the second equation.

$3x+4y= -6$

$3(-2-3y)+4y= -6$

Distribute the 3. Multiply each term inside the parentheses by 3.

$(3*-2)+ (3*-3y)+4y=-6\\-6-9y+4y=-6$

Combine the like terms on the left side.

$-6-5y= -6$

Add 6 to both sides to isolate the variable.

$-6+6-5y=-6+6\\-5y=0$

Divide both sides by -5.

$-5y/-5=0/-5 \\y=0$

Now we know that y is equal to 0 and can substitute it into the first equation and find x.

$x+3(0)=-2$

$x+0=-2 \\x= -2$

x is equal to -2 and y is equal to 0.