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Nesterboy [21]
3 years ago
5

In choosing what music to play at a charity fund raising event, Cory needs to have an equal number of piano sonatas from Mozart,

Brahms, and Schubert. If he is setting up a schedule of the 6 piano sonatas to be played, and he has 18 Mozart, 3 Brahms, and 21 Schubert piano sonatas from which to choose, how many different schedules are possible?
Mathematics
1 answer:
hram777 [196]3 years ago
3 0

Answer:

We conclude that have 96390 different schedules.

Step-by-step explanation:

We know that In choosing what music to play at a charity fund raising event, Cory needs to have an equal number of piano sonatas from Mozart, Brahms, and Schubert.  If he is setting up a schedule of the 6 piano sonatas to be played, and he has 18 Mozart, 3 Brahms, and 21 Schubert piano sonatas.  

We calculate  how many different schedules are possible:

C_2^{18}\cdot C_2^3\cdot C_2^{21}=\frac{18!}{2!(18-2)!}\cdot \frac{3!}{2!(3-2)!}\cdot \frac{21!}{2!(21-2)!}=96390

We conclude that have 96390 different schedules.

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B(n) = -1 (2)^n-1 What is the 5th term in the sequence?
bija089 [108]

Answer:

<h2>The answer is - 16</h2>

Step-by-step explanation:

<h3>b(n) =  - 1 ({2})^{n - 1}</h3>

where

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From the question since we are finding the 5th term

n = 5

Substitute the value into the above formula and solve

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b(5) =  -  1({2})^{5 - 1}  \\  =  - 2 ^{4}

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Find the total surface area of this triangular prism
FinnZ [79.3K]

Answer:

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Step-by-step explanation:

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3 years ago
Right △EFG has its right angle at F, EG=8 , and FG=2 .
d1i1m1o1n [39]

Answer:

Tan E = 2 / 7.75

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Sec G = 4

Step-by-step explanation:

Find the attached document for better illustration of the triangle

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FG = 2 = opposite side of the triangle.

We can use pythagorean theorem to find the adjacent of the triangle since we already know two sides.

EG² = FG² + EF²

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EF = 7.7459 = 7.75

To find the respective trignometric ratio, we can use the relation SOH CAH TOA

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Sin G = 7.75 / 8

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C. Sec G = 1 / cos G

Cos G = adjacent / hypothenus

Sec G = 1 / (adjacent / hypothenus)

Sec G = hypothenus/ adjacent

Sec G = 8 / 2

Sec G = 4

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