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Nesterboy [21]
3 years ago
5

In choosing what music to play at a charity fund raising event, Cory needs to have an equal number of piano sonatas from Mozart,

Brahms, and Schubert. If he is setting up a schedule of the 6 piano sonatas to be played, and he has 18 Mozart, 3 Brahms, and 21 Schubert piano sonatas from which to choose, how many different schedules are possible?
Mathematics
1 answer:
hram777 [196]3 years ago
3 0

Answer:

We conclude that have 96390 different schedules.

Step-by-step explanation:

We know that In choosing what music to play at a charity fund raising event, Cory needs to have an equal number of piano sonatas from Mozart, Brahms, and Schubert.  If he is setting up a schedule of the 6 piano sonatas to be played, and he has 18 Mozart, 3 Brahms, and 21 Schubert piano sonatas.  

We calculate  how many different schedules are possible:

C_2^{18}\cdot C_2^3\cdot C_2^{21}=\frac{18!}{2!(18-2)!}\cdot \frac{3!}{2!(3-2)!}\cdot \frac{21!}{2!(21-2)!}=96390

We conclude that have 96390 different schedules.

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Mr. Granville needs some plywood that is about three over four-inch thick. Which plywood is closest to three over four-inch thic
Makovka662 [10]

Answer:

The plywood that is closest to three over four-inch thick is thirteen over sixteen inches thick

Step-by-step explanation:

we have

3/4 in

Verify each value

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3/4 in=12/16 in ----> multiply by (4/4)

Find the difference

13/16-12/16=1/16 in

case B) 11/32 in

we know that

3/4 in=24/32 in ----> multiply by (8/8)

Find the difference

24/32-11/32==13/32 in

case C) 1/2 in

we know that

1/2 in=2/4 in ----> multiply by (2/2)

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3/4-2/4=1/4 in

case D) 3/8 in

we know that

3/4 in=6/8 in ----> multiply by (2/2)

Find the difference

6/8-3/8=3/8 in

<em>Compare the values of the difference and find the less value</em>

we have

case A) 1/16=2/32 in

case B) 13/32 in

case C) 1/4=8/32 in

case D) 3/8=12/32 in

The less value is case A) 2/32 in

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The plywood that is closest to three over four-inch thick is thirteen over sixteen inches thick

4 0
3 years ago
Could someone help me rnnn?
GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola:  y=3x^2-4

Step-by-step explanation:

Given:

  • y-intercept of parabola: -4
  • parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola:  y=a(x-h)^2+k

(where (h, k) is the vertex and a is some constant)

Substitute point (0, -4) into the equation:

\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}

Substitute point (-2, 8) and ah^2+k=-4 into the equation:

\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}

Substitute point (1, -1) and ah^2+k=-4 into the equation:

\begin{aligned}\textsf{At}\:(1.-1) \implies a(1-h)^2+k &=-1\\a(1-2h+h^2)+k &=-1\\a-2ah+ah^2+k &=-1\\\implies a-2ah-4&=-1\\a(1-2h)&=3\end{aligned}

Equate to find h:

\begin{aligned}\implies a(1+h) &=a(1-2h)\\1+h &=1-2h\\3h &=0\\h &=0\end{aligned}

Substitute found value of h into one of the equations to find a:

\begin{aligned}\implies a(1+0) &=3\\a &=3\end{aligned}

Substitute found values of h and a to find k:

\begin{aligned}\implies ah^2+k&=-4\\(3)(0)^2+k &=-4\\k &=-4\end{aligned}

Therefore, the equation of the parabola in vertex form is:

\implies y=3(x-0)^2-4=3x^2-4

So the vertex of the parabola is (0, -4)

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