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Klio2033 [76]
3 years ago
13

Find the inverse of f(x)=(x−5)/(−4x−2)

Mathematics
1 answer:
uysha [10]3 years ago
7 0

Answer:

{f}^{ - 1} (x)= \frac{  5 - 2x }{ 4x  + 1}

Step-by-step explanation:

The given rational function is

f(x) =  \frac{x - 5}{ - 4x - 2}

Let

y =  \frac{x - 5}{ - 4x - 2}

Interchange x and y

x=  \frac{y- 5}{ - 4y - 2}

Cross multiply

x( - 4y - 2)= y- 5

Expand

- 4xy   - 2x= y- 5  \\ - 4xy  - y=  2x - 5 \\y( - 4x - 1)=  2x - 5

Solve for y;

y= \frac{  2x - 5}{ - 4x - 1}

or

y= \frac{  5 - 2x }{ 4x  + 1}

Therefore

{f}^{ - 1} (x)= \frac{  5 - 2x }{ 4x  + 1}

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3 years ago
how is x > 4(with a dash under the symbol in the middle,symbol is not on my keyboard)graphed on a number line?​
soldi70 [24.7K]

Answer:

The point on the line is not filled in (so just a white circle) because the sign is an "equal to" sign. The line always faces the opposite side of the jaws, so in the case of x > 4, the line goes right starting from the hollow point above 4.

3 0
3 years ago
A radio active isotope decays according to the exponential decay equation where t is in days. Round to the thousandths place. Th
Whitepunk [10]
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8 0
3 years ago
Add. Your answer should be a polynomial in standard form. ( − 8 y 2 − 9 y ) + ( 8 y 3 + 9 y 2 − 2 y ) =
aliya0001 [1]
(−8* y^2−9*y)+(8*y^3+9*y^2−2*y) 
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=−8* y^2−9*y+8*y^3+9*y^2−2*y  
then group terms in decreasing degree of y (variable)
=+8*y^3 −8* y^2+9*y^2  −9*y−2*y
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6 0
3 years ago
The graph of the function f(x) = (x +2)(x + 6) is shown
dalvyx [7]

The true about the domain and the range of the function is:

The domain is all real numbers, and the range is all real  numbers

greater than or equal to -4 ⇒ 1st answer

Step-by-step explanation:

f(x) = (x + 2)(x + 6) is a quadratic function with 2 factors (x + 2) and (x + 6)

By multiplying its two factors we will find the form of the quadratic function

∵ (x)(x) = x²

∵ (x)(6) = 6x

∵ (2)(x) = 2x

∵ (2)(6) = 12

∴ f(x) = x² + 6x + 2x + 12

- By adding like terms

∴ f(x) = x² + 8x + 12

The quadratic function represented graphically by a parabola

Look to the attached figure

The x-coordinate of the vertex point of the parabola h = \frac{-b}{a}

where b is the coefficient of x and a is the coefficient of x²

∵ f(x) = x² + 8x + 12

∴ a = 1 and b = 8

∴ h = \frac{-8}{2*1}=-4

The y-coordinate of the vertex point is k = f(h)

∵ h = -4

∴ k = f(-4)

∴ k = (-4)² + 8(-4) = 12 = 16 - 32 + 12

∴ k = -4

∴ The vertex point of the parabola is (-4 , -4)

∵ The parabola is opened upward

∴ Its vertex is minimum point

∴ The minimum value of f(x) is y = -4

∵ The domain of the function is the values of x

∵ The range of the function is the values of y corresponding to the

   values of x

∵ x can be any real numbers

∴ x ∈ R, where R is the set of real numbers

∴ The domain of f(x) is all real numbers

∵ The minimum value of f(x) is y = -4

∴ y can be any real number greater than or equal to -4

∴ y ≥ -4

∴ The range is all real number greater than or equal to -4

The true about the domain and the range of the function is:

The domain is all real numbers, and the range is all real  numbers

greater than or equal to -4

Learn more:

You can learn more about quadratic function in brainly.com/question/1332667

#LearnwithBrainly

7 0
3 years ago
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