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mario62 [17]
3 years ago
13

Add. Your answer should be a polynomial in standard form. ( − 8 y 2 − 9 y ) + ( 8 y 3 + 9 y 2 − 2 y ) =

Mathematics
1 answer:
aliya0001 [1]3 years ago
6 0
(−8* y^2−9*y)+(8*y^3+9*y^2−2*y) 
first, remove extraneous parentheses (or distribute if negative)
=−8* y^2−9*y+8*y^3+9*y^2−2*y  
then group terms in decreasing degree of y (variable)
=+8*y^3 −8* y^2+9*y^2  −9*y−2*y
simply expression by adding/subtracting similar terms
=+8*y^3 +y^2  −11*y
to give the final answer.
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How many sides does the polygon have?<br> 8<br> 10<br> 12<br> 15
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8 0
3 years ago
Factor the expression completely.
evablogger [386]

Answer:

Factoring the expression xy^4+x^4y^4 completely we get \mathbf{xy^4(x+1)(x^2-x+1)}

Step-by-step explanation:

We need to factor the expression xy^4+x^4y^4 completely

We need to find common terms in the expression.

Looking at the expression, we get xy^4 is common in both terms, so we can write:

xy^4+x^4y^4\\=xy^4(1+x^3)

So, taking out the common expression we get: xy^4(1+x^3)

Now, we can factor the term (1+x^3) or we can write (x^3+1) by using formula:

a^3+b^3=(a+b)(a^2-ab+b^2)

So, we get:

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Therefor factoring the expression xy^4+x^4y^4 completely we get \mathbf{xy^4(x+1)(x^2-x+1)}

6 0
3 years ago
2x - 5y=-15<br> can someone walk me through this?
HACTEHA [7]
The equation given in the question has two unknown variables in the form of "x" and "y". The exact value of "x" and "y" cannot be determined as two equations are needed to get to the exact values of "x" and "y". This equation can definitely be used to show the way for determining the values of "x" in terms of "y"and the value of "y" in terms of "x". Now let us check the equation given.
2x - 5y = - 15
2x = 5y - 15
2x = 5(y - 3)
x = [5(y - 3)]/2
Similarly the way the value of y can be determined in terms of "x" can also be shown.
2x - 5y = - 15
-5y = - 2x - 15
-5y = -(2x + 15)
5y = 2x + 15
y = (2x +15)/5
   = (2x/5) + (15/5)
   = (2x/5) + 3
So the final value of x is [5(y -3)]/2 and the value of y is (2x/5) + 3.
3 0
3 years ago
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