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3 years ago

15

‼️10 point‼️URGENT‼️

1 answer:

Elena-2011 [213]3 years ago

4 0

D. y=-3/10x+1/2

Step-by-step explanation:

Using rise/run you can count the units the line moves from one point to another, from the left point to the right point the line travels down 3 and over 10 so you get -3 as your rise (it is negative because the line is traveling downwards) and 10 as your run, so your slop is -3/10. By looking at the graph you can see that your y-intercept is 1/2. SO when plugged into y=mx+b with m as -3/10 and b as 1/2 you get the equation y=-3/10x+1/2, or letter D.

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3 years ago

Read 2 more answers

Point G is located at (6, 2) on the coordinate plane. Point G is reflected over the y -axis to create point G^ prime . What orde

Lilit [14]

Answer:

The ordered pair that best describes the location of G' is (-6,2).

Step-by-step explanation:

Reflecting a point over the y-axis:

When a point (x,y) is reflected over the y-axis, it's x coordinate is multiplied by -1, while the y-coordinate stays the same. Thus:

(x,y) -> (-x,y).

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When reflected over the y-axis:

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The ordered pair that best describes the location of G' is (-6,2).

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2 years ago

1. Carter will install fencing all around the flat area of his

MariettaO [177]

Answer:

Amount of fencing required = 75 yards

Step-by-step explanation:

Distance between the two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the formula,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between A(3, 6) and B(3, -2) = $\sqrt{(3-3)^2+(6+2)^2}$

= 8 yards

Distance between B(3, -2) and C(-7, 4) = $\sqrt{(3+7)^2+(-2-4)^2}$

= $\sqrt{136}$

= 11.66 ≈ 12 yards

Distance between C(-7, 4) and D(-7, -2) = $\sqrt{(-7+7)^2+(4+2)^2}$

= 6 yards

Distance between D(-7, -2) and E(-3, -2) = $\sqrt{(-7+3)^2+(-2+2)^2}$

= 4 yards

Distance between E(-3, -2) and F(-3, -8) = $\sqrt{(-3+3)^2+(-2+8)^2}$

= 6 yards

Distance between F(-3, -8) and G(3, -8) = $\sqrt{(-3-3)^2+(-8+8)^2}$

= 6 yards

Distance between G(3, -8) and H(10, -12) = $\sqrt{(3-10)^2+(-8+12)^2}$

= $\sqrt{49+16}$

= $\sqrt{65}$

= 8.06 ≈ 8 yards

Distance between H(10, -12) and J(10, 6) = $\sqrt{(10-10)^2+(-12-6)^2}$

= 18 yards

Distance between A(3, 6) and J(10, 6) = $\sqrt{(10-3)^2+(6-6)^2}$

= 7 yards

Since length of fence required = perimeter of the flat area

Perimeter of the given area = 8 + 12 + 6 + 4 + 6 + 6 + 8 + 18 + 7

= 75 yards

Therefore, amount of fencing required = 75 yards

8 0

3 years ago

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago