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svp [43]
4 years ago
10

WILL GIVE BRAINLIEST

Mathematics
1 answer:
mylen [45]4 years ago
7 0

Answer:

342

Step-by-step explanation:

,81×2+90×2

162+180

342

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What is the value of i^3
PIT_PIT [208]

Answer:

The answer is the last one, -i.

Hope this helped!

8 0
4 years ago
Read 2 more answers
-x+y+z=-1<br> -x+4y-5z=-16<br> 5x-4y-7z=0
ehidna [41]

Answer:

8

Step-by-step explanation:

3 0
3 years ago
The radius of the inscribed circle is 10in what is the perimeter of square CABD
Monica [59]

Answer:


Step-by-step explanation:

Diameter = 10 * 2 = 20in

Diameter of inscribed circle = Length of one side of square

Perimeter of square = 4 * length

P = 4 * 20 = 80in

6 0
4 years ago
Simplify completely..........​
vitfil [10]

Answer:

\frac{x}{x-1}

Step-by-step explanation:

\frac{3x^2 - 1}{x^2 - 1} - \frac{2x + 1}{x + 1}                                          [ \ x^ 2- 1 = (x-1)(x + 1) \ ]

= \frac{3x^2 - 1}{(x-1)(x  + 1 )} - \frac{2x + 1}{x + 1}\\\\=\frac{(3x^2 - 1)-(2x + 1)(x-1)}{(x + 1)(x-1)}                        [\ Taking \ LCM \  ]

= \frac{(3x^2 - 1)- (2x^2 - 2x + x - 1)}{(x+1)(x-1)}\\\\=\frac{3x^2 - 1 - 2x^2 + x + 1 }{(x+1)(x-1)}\\\\=\frac{x^2 +x}{(x+1)(x-1)}\\\\=\frac{x(x+1)}{(x+1)(x-1)}\\\\=\frac{x}{x-1}

<em><u>Finding LCM :</u></em>

Example :

                 \frac{1}{6} + \frac{1}{3}

6 = 2  x   3

3 = 1   x   3

                \frac{1}{2 \times 3} + \frac{1}{ 3} = \frac{1}{2 \times 3} + \frac{1 \times 2}{ 3 \times 2}  

[ To make the denominators same : the second fraction is multiplied and divided by 2 ]

Similarly :

 (x^2 - 1 ) = (x -1)(x+1)\\\\(x + 1)  = 1 \times (x + 1)

Same rule we applied : multiplied the numerator and denominator of the second term with ( x - 1 )

Therefore the second term becomes ,

                                       \frac{2x + 1}{x + 1} = \frac{(2x + 1)(x - 1)}{(x + 1)( x - 1)}

7 0
3 years ago
Consider the following.f(x)=74 – x2Find the x-values at which f is not continuous. Which of the discontinuities are removable?
tensa zangetsu [6.8K]

Answer

given,

f(x) = 74 - x²

A function is continuous when it is differential at all the points.

f'(x) =\dfrac{d}{dx}(74-x^2)

f'(x) =- 2 x

so, the given function is continuous for all the value of x.

We should know that if a function is quadratic then it is differential at all the point.  And if it is differential then it is definitely continuous.

Hence, there is no discontinuous point present in the equation.

6 0
4 years ago
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