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vovikov84 [41]
3 years ago
5

What is the value of i^3

Mathematics
2 answers:
PIT_PIT [208]3 years ago
8 0

Answer:

The answer is the last one, -i.

Hope this helped!

vodomira [7]3 years ago
7 0

Answer:

- i

Step-by-step explanation:

i = \sqrt{-1} ⇒ i² = (\sqrt{-1})² = - 1, thus

i³ = i² × i = - 1 × i = - i

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the perimeter of a triangle is 59 in. The longest side is 11in. longer than the medium side, and the medium side is 3in longer t
Nataly_w [17]
Let the length of shortest side be - x
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Light travels at 3.0 x 108 km/s. How far does light travel in 5 minutes? A) 1.5 x 1010 km B) 1.5 x 1011 km C) 9.0 x 109 km D) 9.
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<span>D) 9.0 x 10^10 km This is more an exercise in handling scientific notation than anything else. Since we have the distance that light travels in 1 second and we want to calculate how far it travels in 5 minutes, we must first calculate how many seconds are in 5 minutes. Simply multiplying 5 by 60 gives us 300 seconds. Now we need to multiply 300 by 3.0x10^8 km. So 300 * 3.0x10^8 = ? We could first convert 300 into scientific notion, but it's easier to just leave it along and assume that it's 300 x 10^0. So 300 times 3 is 900. And since 0 plus 8 is 8, we have as the answer: 900 x 10^8 But we're not done. The significand has to be greater than or equal to 1 and less than 10. So let's divide 900 by 100 and add 2 to the exponent. So we get 9 x 10^10 Finally, since our data had 2 significant figures, our result should have that as well. So let's add the 2nd digit getting: 9.0 x 10^10 So we know that light travels 9.0x10^10 km in 5 minutes, and that answer matches option "D" from the available choices.</span>
4 0
3 years ago
Need help fast plz for my pre calc exam
bezimeni [28]

Answer:

<em>h = 8.54 units</em>

Step-by-step explanation:

<u>The Law of Cosines </u>

It relates the length of the sides of a triangle with one of its internal angles.

Let a,b, and c be the length of the sides of a given triangle, and x the included angle between sides a and b, then the following relation applies:

c^2=a^2+b^2-2ab\cos x

Since we know the values of all three side lengths, we solve the equation for x:

\displaystyle \cos x=\frac{a^2+b^2-c^2}{2ab}

For the triangle ABC in the image, a=10, b=15, c=13, thus:

\displaystyle \cos A=\frac{10^2+15^2-13^2}{2*10*15}

\displaystyle \cos A=\frac{156}{300}

\displaystyle \cos A=0.52

Thus, A = 58.67°

For the right triangle of height h and hypotenuse 10, we use the sine ratio:

\displaystyle \sin 58.67^\circ=\frac{h}{10}

Solving for h:

h = 10\sin 58.67^\circ

h = 8.54 units

6 0
3 years ago
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