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Dahasolnce [82]
3 years ago
11

Write 0.895 with 95 repeating on and on as a simplified fractionPLZ HELP WILL GIVE BRANLIEST

Mathematics
2 answers:
Alchen [17]3 years ago
8 0

Answer:

\huge\boxed{x = \frac{887}{990}}

Step-by-step explanation:

The number given is 0.895..........

Let x = 0.895........

Then

10x = 8.95.......   --------(1)

1000x = 985.95........   --------(2)

Subtracting (1) from (2)

1000x - 10x = 985.95..... - 8.95......

990 x = 887

Dividing both sides by 990

x = \frac{887}{990}   (In simplest form)

SashulF [63]3 years ago
5 0

Answer:

887/990

Step-by-step explanation:

0.8959595....

895.95 - 8.95 = 887

1000 - 10 = 990

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Please dont ignore, Need help!!! Use the law of sines/cosines to find..
Ket [755]

Answer:

16. Angle C is approximately 13.0 degrees.

17. The length of segment BC is approximately 45.0.

18. Angle B is approximately 26.0 degrees.

15. The length of segment DF "e" is approximately 12.9.

Step-by-step explanation:

<h3>16</h3>

By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.

For triangle ABC:

  • \sin{A} = \sin{103\textdegree{}},
  • The opposite side of angle A a = BC = 26,
  • The angle C is to be found, and
  • The length of the side opposite to angle C c = AB = 6.

\displaystyle \frac{\sin{C}}{\sin{A}} = \frac{c}{a}.

\displaystyle \sin{C} = \frac{c}{a}\cdot \sin{A} = \frac{6}{26}\times \sin{103\textdegree}.

\displaystyle C = \sin^{-1}{(\sin{C}}) = \sin^{-1}{\left(\frac{c}{a}\cdot \sin{A}\right)} = \sin^{-1}{\left(\frac{6}{26}\times \sin{103\textdegree}}\right)} = 13.0\textdegree{}.

Note that the inverse sine function here \sin^{-1}() is also known as arcsin.

<h3>17</h3>

By the law of cosine,

c^{2} = a^{2} + b^{2} - 2\;a\cdot b\cdot \cos{C},

where

  • a, b, and c are the lengths of sides of triangle ABC, and
  • \cos{C} is the cosine of angle C.

For triangle ABC:

  • b = 21,
  • c = 30,
  • The length of a (segment BC) is to be found, and
  • The cosine of angle A is \cos{123\textdegree}.

Therefore, replace C in the equation with A, and the law of cosine will become:

a^{2} = b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}.

\displaystyle \begin{aligned}a &= \sqrt{b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}}\\&=\sqrt{21^{2} + 30^{2} - 2\times 21\times 30 \times \cos{123\textdegree}}\\&=45.0 \end{aligned}.

<h3>18</h3>

For triangle ABC:

  • a = 14,
  • b = 9,
  • c = 6, and
  • Angle B is to be found.

Start by finding the cosine of angle B. Apply the law of cosine.

b^{2} = a^{2} + c^{2} - 2\;a\cdot c\cdot \cos{B}.

\displaystyle \cos{B} = \frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}.

\displaystyle B = \cos^{-1}{\left(\frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}\right)} = \cos^{-1}{\left(\frac{14^{2} + 6^{2} - 9^{2}}{2\times 14\times 6}\right)} = 26.0\textdegree.

<h3>15</h3>

For triangle DEF:

  • The length of segment DF is to be found,
  • The length of segment EF is 9,
  • The sine of angle E is \sin{64\textdegree}}, and
  • The sine of angle D is \sin{39\textdegree}.

Apply the law of sine:

\displaystyle \frac{DF}{EF} = \frac{\sin{E}}{\sin{D}}

\displaystyle DF = \frac{\sin{E}}{\sin{D}}\cdot EF = \frac{\sin{64\textdegree}}{39\textdegree} \times 9 = 12.9.

7 0
3 years ago
Please answer clear i need answers now please
Salsk061 [2.6K]

Answer:

The answers would be:

9: $421.54

10: $872

11: $4,706.66

12: $645.83

13: $626.26

14: $3,981.22

15: $1,110.28

16: $210.50

5 0
2 years ago
5. Class 7887 has 2:7 math classes daily. How many math classes do they have
ANTONII [103]

Answer:

56.7

Step-by-step explanation:

2.7 x 21 = 56.7

5 0
3 years ago
Solve 7d + d - 4d - 7 - 5d
Butoxors [25]
-1d-7 is the answer I'm pretty sure
6 0
3 years ago
Read 2 more answers
Help plss !! Will give branliest to who ever has the best answer
ozzi

Answer:

a c and e hope it helps :D

Step-by-step explanation:

5 0
2 years ago
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