Answer:
9/20 as a faction as a decimal 0.45
Step-by-step explanation:
Simplify 3/5 • 3/4
I hope this help
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
The solutions are:
Step-by-step explanation:
Considering the expression
Solving the expression
So,
Therefore, the solutions are:
80words=1min so you would multiply 80 by 20 which is 1,600 words for 20 minutes
