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brilliants [131]
2 years ago
9

Is an arithmetic sequence a function?

Mathematics
1 answer:
Sphinxa [80]2 years ago
3 0
Yes it is a linear function
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2x + 2y = 6<br> 3x − 2y = 29
Mazyrski [523]

Answer:

x = 7

y = -4

Step-by-step explanation:

5x = 35

x=7

14 + 2y = 6

2y = -8

y = -4

7 0
3 years ago
Please help: linear algebra problem. (Linear combinations)
DochEvi [55]

Answer:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

This tells us that:

A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]

b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right].

So we want to find a way to express this as:

Ax=b where x is the scalar vector, \left[\begin{array}{ccc}c\\d\end{array}\right].

So we can write this as:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

3 0
2 years ago
Help me please help me helpm
Firlakuza [10]

Answer:

nhjggggggggggggj

Step-by-step explanation:

5 0
3 years ago
2+2?<br> please answer i need to graduate from highschool
tensa zangetsu [6.8K]

Hope this helps Answer:

4

6 0
2 years ago
Which statement is not true? a.All nunbers are natural numbers.b.Fractions are rational numbers.c.Zero is an integer.
DiKsa [7]
I believe that b.Fractions are rational numbers is not true

sorry if its wrong
6 0
3 years ago
Read 2 more answers
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